Question

A virtual, erect and diminished image is formed by a concave lens, when the object is:
(A) Beyond 2F
(B) At 2F
(C) Between F and 2F
(D) All the above

Answer 1

Hint We know that a concave lens is defined as a lens that possesses at least one surface that curves inwards. It is considered to be a diverging lens, which means that it spreads out light rays that have been refracted through it. The concave lens is thinner at its centre than at its edges, and is used to correct short-sightedness. Based on this concept we have to solve this question.

Complete step by step answer
We know that a concave lens always gives a virtual, erect and diminished image whatever may be the position of the object.
There are some properties which define the concave lens which include negative focal length and the incident rays always diverge away from the principal axis.
The position of the images when the object is placed at infinity, between O and F and any position between infinity and O are given below in the diagrammatic representation.
In the first diagram we have the object in the infinity position:

In the second diagram we have the object in the place that is between the O and F:

In the third diagram we have the object in the position that is placed between O and infinity:


Note We know that the principal axis is defined as the line that passes through the centre of curvature of a lens so that the light is either reflected or refracted. In the normal eye the optic axis is the direction in which objects are seen mostly distinctly optic axis.
We know that concave mirrors can produce both real and virtual images, they can be upright, in case the image is virtual or it is inverted if it is real. They can be behind the mirror (if it is virtual) or in front of the mirror (if it is real). The properties of the image are also enlarged, reduced or the same size as the object.