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Calculate the monthly (30 days a month) Energy Bill for a domestic application where 5 bulbs each of 60 W are running for 10 hrs a day, 150 W electric Fan 4 numbers running for 5 hrs a day. One number Geyser of 2kW operated for 30 mins. In a day and refrigerator of 800 W, one number for 20 hrs. The cost of an electric unit is Rs 7/- per unit. (Formula based & data interpretation)

Answer
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Hint: For calculating electricity cost, first of all find out the power on which each electric device is operated. Here, make sure that power is in Kilowatts only if not then convert watts to kilowatts (1 watt = kilowatts/1000). Then, find out the kilowatts an electronic appliance uses per month. find out the number of hours for which electronic device is on per day and make sure to convert the time in hours only. Now, finally find out the electricity cost.

Complete step by step solution:
S.no.Electronic devicePower (P)Time (T)
1.5 Bulbs60 Watts = 60/1000 = 0.06 kiloWatts10 hours
2.4 Electric fans150 Watts = 150/1000 = 0.15 kiloWatts5 hours
3.1 Geyser2 kiloWatts30 minutes = 0.5 hours
4.1 Refrigerator800 Watts = 800/1000 = 0.8 kiloWatts20 hours


Formula for energy consumed, E=Pt
Where P = power and t = time
Energy consumed by 5 bulbs of power, E1=5×0.06×10×30=90kWh
Here, number of bulbs =5
Power consumed = 0.06kW
Time = 30×10hrs
Energy consumed by 4 electric fans, E2=4×0.15×5×30=90kWh
Here, number of electric fans =4
Power consumed = 0.15kW
Time = 30×5hrs
Energy consumed by 1 Geyser, E3=1×2×0.5×30=30kWh
Here, number of Geyser=1
Power consumed = 2kW
Time = 30×0.5hrs
Energy consumed by 1 refrigerator, E4=1×0.8×20×30=480kWh
Here, number of refrigerator =1
Power consumed = 0.8kW
Time = 30×20hrs
Total energy consumed by the electric devices in one month
90kWh+90kWh+30kWh+480kWh=690kWh
The cost of an electric unit is Rs 7/- per unit
So, total cost of 690kWh is given by
690×7=4830/

Therefore, the monthly (30 days a month) Energy Bill is Rs4830.

Note: A watt hour and kilowatt hour are practical units of electric energy. The commercial unit of electric energy is kilowatt hour (kWh), where 1kWh=1000Wh=3.6×106J. Electric power is the rate at which electric energy is consumed. SI unit of electric power is Watt.