Question

Consider the following transformations
(I) $Xe{F}_6+NaF\to N{a}^{+}{[Xe{F}_7]}^{-}$
(II) $2PC{l}_5(s)\to {[PC{l}_4]}^{+}{[PC{l}_5]}^{-}$
(III) ${[Al{(H_{2}O)}_6]}^{3+}+H_{2}O\to {[Al{(H_{2}O)}_{5}OH]}^{2+}+H_3{O}^{+}$

Possible transformation is:
(A) I, II, III
(B) I, III
(C) I, II
(D) II, III

Answer 1

Hint: One of the basic fundamental rules to check whether a transformation or a reaction is possible or not is by checking whether the elements in the reactant and products are balanced or not.

Complete step by step solution:
-In the first option, the reaction is between Xenon fluoride and Sodium fluoride which gives an unstable compound. Xenon fluoride here acts as a fluoride donor and gives a balanced equation.

$Xe{F}_6+NaF\to N{a}^{+}{[Xe{F}_7]}^{-}$

-In the second option, the phosphorus pentachloride is undergoing self ionization in the polar solutions. The reaction is also balanced. This is a reversible reaction. In dilute solutions, the reaction occurs in the forward direction, but at higher concentrations, the reaction in the backward direction becomes more prevalent. The $$PC{l}_5$$in the reactant is in $s{p}^{3}d$hybridization, while ${[PC{l}_4]}^{+}$and ${[PC{l}_5]}^{-}$in the products are in $s{p}^3$ and $s{p}^3{d}^2$ hybridization respectively.

$2PC{l}_5(s)\to {[PC{l}_4]}^{+}{[PC{l}_5]}^{-}$

-In the third option, Aluminium Hexa-aqua complex ion on dissociation leads to the formation of the conjugate base that is ${[Al{(H_{2}O)}_{5}OH]}^{2+}$and a proton which combines with water molecule forming a hydronium ion. $A{l}^{3+}$being highly charged and small attracts water molecule and binds via dative covalent bonds and it also attracts the lone pair of electrons from the O-H bond and the water molecule splits into a proton and a hydroxide ion.

${[Al{(H_{2}O)}_6]}^{3+}+H_{2}O\to {[Al{(H_{2}O)}_{5}OH]}^{2+}+H_3{O}^{+}$

So, option (A) is correct.

Note: $Xe{F}_6$is solid at room and it readily sublimes into yellow vapours. It can be prepared by heating $Xe{F}_2$ at about $300{}^{\circ }C$and 60 atm pressure, but with the use of $Ni{F}_2$as a catalyst, the temperature can be lowered to $120{}^{\circ }C$. $PC{l}_5$is one of the most important phosphorus chlorides which is a colourless, water-sensitive, and moisture-sensitive solid chemical compound. It is used as a chlorinating reagent. It is highly corrosive and reacts violently with water, this is a very dangerous substance.