
When the current and voltage of an electric circuit is given. Then power can be calculated by:
A. multiplying the current by the difference between the voltage going into and going out of the device.
B. multiplying the resistance by the resistance and the current.
C. multiplying the voltage by the difference between going into and going out of the device.
D. multiplying the current by the voltage.
E. multiplying the current by the resistance.
Answer
133.5k+ views
Hint Power is defined as the rate of the energy is transformed or transferred over time. We measure power in units of joules/second. It is also measured in watts.
Complete step by step solution
An electric circuit is capable of transferring power. Current is the rate of the flow of charge and voltage measures the energy transferred per unit of charge and the current is analysis as the number of the charges per unit time passing through a boundary. Since current is the amount of charge passing through a boundary in a fixed amount of time.
Power is defined as the current in the circuit and it is multiplied by the voltage of the energy source like battery.
The Power of a battery is expressed as,
Power $P = V \times I$
Here, V is the voltage of the battery.
Voltage is proportional to the current and the resistance of the battery.
$V = IR.$
Substitute,
$P = \left( {IR} \right) \times R$
$P = I{R^2}$.
Therefore, power can be calculated by the multiplying by the current and the resistance.
Hence, from the above options, option E is correct.
Note In the question, we solve by using the equation of power. Power is proportional to the voltage and the current. By using the equation of ohm’s law we substitute that in the equation of the power. It says that the current through a conductor between the points is proportional to the voltage across the points.
Complete step by step solution
An electric circuit is capable of transferring power. Current is the rate of the flow of charge and voltage measures the energy transferred per unit of charge and the current is analysis as the number of the charges per unit time passing through a boundary. Since current is the amount of charge passing through a boundary in a fixed amount of time.
Power is defined as the current in the circuit and it is multiplied by the voltage of the energy source like battery.
The Power of a battery is expressed as,
Power $P = V \times I$
Here, V is the voltage of the battery.
Voltage is proportional to the current and the resistance of the battery.
$V = IR.$
Substitute,
$P = \left( {IR} \right) \times R$
$P = I{R^2}$.
Therefore, power can be calculated by the multiplying by the current and the resistance.
Hence, from the above options, option E is correct.
Note In the question, we solve by using the equation of power. Power is proportional to the voltage and the current. By using the equation of ohm’s law we substitute that in the equation of the power. It says that the current through a conductor between the points is proportional to the voltage across the points.
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

Sign up for JEE Main 2025 Live Classes - Vedantu

JEE Main Books 2023-24: Best JEE Main Books for Physics, Chemistry and Maths

JEE Main 2023 April 13 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 11 Shift 2 Question Paper with Answer Key

JEE Main 2023 April 10 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Wheatstone Bridge for JEE Main Physics 2025

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Diffraction of Light - Young’s Single Slit Experiment

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

If a wire of resistance R is stretched to double of class 12 physics JEE_Main

JEE Advanced 2024 Syllabus Weightage

Current Loop as Magnetic Dipole and Its Derivation for JEE
