Answer
373.1k+ views
Hint: Breakdown happens when the electric field enhances strongly enough so that it can pull electrons from the molecules of a material and ionizes them. The free electrons are increased in speed by the field which strike other atoms which results in creating more free electrons.
Complete answer:
Break down of a diode usually occurs in the reverse biased state. Under the reverse biased state of a PN diode, the positive end of the battery is connected to the n-side of the diode and the negative end is connected to the p-side of the diode. As an outcome of this, electrons will be drawn in respect to the off-side and the holes will be drawn in respect to the side of the p-side. There are two types of breakdown that happen in a diode. They are Zener breakdown and Avalanche breakdown.
![](https://www.vedantu.com/question-sets/b04321ca-6458-49e1-b474-f1f993ec871d2222210794794056751.png)
Zener diode:
The phenomena of Zener breakdown that happens in a pn junction diode of heavy doping and a thin junction, that is in a way that the size of the depletion layer is very small. Zener breakdown is not that the diode is damaged. As the current is only because of drifting of electrons, there are certain limitations to the increase in current.
Avalanche breakdown:
The phenomenon of Avalanche breaks down that happens in a pn junction diode which is averagely doped that has the thickest junction, that is the thickness of the depletion section is high. This phenomenon normally takes place when there is a greater reverse voltage. Which is evidently greater than that of the Zener breakdown voltage. That is when we increase the applied reverse voltage, the electric field over the junction will keep on rising.
Therefore, Avalanche breakdown in a diode occurs when the reverse bias exceeds a certain value.
Hence, the option (C), reverse bias exceeds certain value is the correct.
Note: In a Zener the current that is essential to split the electrons from the covalent bonds can be obtained with the help of lower voltage than that of the avalanche, which is due to the thin layer of the pn junction. Since the thickness of the depletion in the avalanche is higher than that of the Zener the required electrons to split the covalent bond is greater.
Complete answer:
Break down of a diode usually occurs in the reverse biased state. Under the reverse biased state of a PN diode, the positive end of the battery is connected to the n-side of the diode and the negative end is connected to the p-side of the diode. As an outcome of this, electrons will be drawn in respect to the off-side and the holes will be drawn in respect to the side of the p-side. There are two types of breakdown that happen in a diode. They are Zener breakdown and Avalanche breakdown.
![](https://www.vedantu.com/question-sets/b04321ca-6458-49e1-b474-f1f993ec871d2222210794794056751.png)
Zener diode:
The phenomena of Zener breakdown that happens in a pn junction diode of heavy doping and a thin junction, that is in a way that the size of the depletion layer is very small. Zener breakdown is not that the diode is damaged. As the current is only because of drifting of electrons, there are certain limitations to the increase in current.
Avalanche breakdown:
The phenomenon of Avalanche breaks down that happens in a pn junction diode which is averagely doped that has the thickest junction, that is the thickness of the depletion section is high. This phenomenon normally takes place when there is a greater reverse voltage. Which is evidently greater than that of the Zener breakdown voltage. That is when we increase the applied reverse voltage, the electric field over the junction will keep on rising.
Therefore, Avalanche breakdown in a diode occurs when the reverse bias exceeds a certain value.
Hence, the option (C), reverse bias exceeds certain value is the correct.
Note: In a Zener the current that is essential to split the electrons from the covalent bonds can be obtained with the help of lower voltage than that of the avalanche, which is due to the thin layer of the pn junction. Since the thickness of the depletion in the avalanche is higher than that of the Zener the required electrons to split the covalent bond is greater.
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