
What will happen when dilute sulphuric acid is added to sodium sulfite?
(A) $N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{3}}+{{H}_{2}}O$
(B) $N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{3}}+S{{O}_{2}}+{{H}_{2}}O$
(C) $N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}+{{H}_{2}}O$
(D) $N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}+{{H}_{2}}O$
Answer
141k+ views
Hint: The reaction between dilute sulphuric acid and sodium sulfite is a double displacement reaction. Double displacement reactions are the reactions in which two compounds react by an exchange of ions to form two new compounds.
Complete step by step solution:
-In double displacement reactions, the positive ions exchange with negative ions. The general reaction is represented by the following general equation-
${{A}^{+}}{{B}^{-}}+{{C}^{+}}{{D}^{-}}\to {{A}^{+}}{{D}^{-}}+{{C}^{+}}{{B}^{-}}$
-The reaction between sulphuric acid and sodium sulfite occurs in the following two steps-
(i) The first step involves the reaction of sulphuric acid with sodium sulfite giving sodium sulfite and sulfurous acid as products.
${{H}_{2}}S{{O}_{4}}+N{{a}_{2}}S{{O}_{3}}\to N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}S{{O}_{3}}$
(ii) In the second step, sulfurous acid formed in the first step being highly unstable, decomposes spontaneously into sulfur dioxide and water.
${{H}_{2}}S{{O}_{3}}\to S{{O}_{2}}+{{H}_{2}}O$
Thus, the overall reaction can be given as-
${{H}_{2}}S{{O}_{4}}+N{{a}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}+{{H}_{2}}O$
So, the correct answer is option C.
Note: You should not get confused between sodium sulfate and sodium sulfite. Sodium sulfate is an inorganic salt of sodium with chemical formula as $N{{a}_{2}}S{{O}_{4}}$, which exists in three forms. The anhydrous form sodium sulfate is known as thenardite, a heptahydrate form is a rare form, and the decahydrate form is known as mirabilite. Sodium sulfite is an inorganic compound which a pale yellow, water-soluble solid with the chemical formula sodium sulfate minus one oxygen, that is $N{{a}_{2}}S{{O}_{3}}$. Sodium sulfite is used commercially as a preservative and an antioxidant. Another form of sodium sulfite is also known which is heptahydrate but it is not of much use due to its greater susceptibility towards oxidation by air. Sodium sulfite is used commercially in the pulp and paper industry, as an oxygen scavenger agent and is used to treat water being fed to steam boilers to avoid corrosion issues. It is also used as a reducing agent in the textile industry as a bleaching, desulfurizing, and dechlorinating agent. In the production of sodium thiosulphate, it is used as a reagent in sulfonation and sulfomethylation agents.
Complete step by step solution:
-In double displacement reactions, the positive ions exchange with negative ions. The general reaction is represented by the following general equation-
${{A}^{+}}{{B}^{-}}+{{C}^{+}}{{D}^{-}}\to {{A}^{+}}{{D}^{-}}+{{C}^{+}}{{B}^{-}}$
-The reaction between sulphuric acid and sodium sulfite occurs in the following two steps-
(i) The first step involves the reaction of sulphuric acid with sodium sulfite giving sodium sulfite and sulfurous acid as products.
${{H}_{2}}S{{O}_{4}}+N{{a}_{2}}S{{O}_{3}}\to N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}S{{O}_{3}}$
(ii) In the second step, sulfurous acid formed in the first step being highly unstable, decomposes spontaneously into sulfur dioxide and water.
${{H}_{2}}S{{O}_{3}}\to S{{O}_{2}}+{{H}_{2}}O$
Thus, the overall reaction can be given as-
${{H}_{2}}S{{O}_{4}}+N{{a}_{2}}S{{O}_{4}}\to N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}+{{H}_{2}}O$
So, the correct answer is option C.
Note: You should not get confused between sodium sulfate and sodium sulfite. Sodium sulfate is an inorganic salt of sodium with chemical formula as $N{{a}_{2}}S{{O}_{4}}$, which exists in three forms. The anhydrous form sodium sulfate is known as thenardite, a heptahydrate form is a rare form, and the decahydrate form is known as mirabilite. Sodium sulfite is an inorganic compound which a pale yellow, water-soluble solid with the chemical formula sodium sulfate minus one oxygen, that is $N{{a}_{2}}S{{O}_{3}}$. Sodium sulfite is used commercially as a preservative and an antioxidant. Another form of sodium sulfite is also known which is heptahydrate but it is not of much use due to its greater susceptibility towards oxidation by air. Sodium sulfite is used commercially in the pulp and paper industry, as an oxygen scavenger agent and is used to treat water being fed to steam boilers to avoid corrosion issues. It is also used as a reducing agent in the textile industry as a bleaching, desulfurizing, and dechlorinating agent. In the production of sodium thiosulphate, it is used as a reagent in sulfonation and sulfomethylation agents.
Recently Updated Pages
Difference Between Crystalline and Amorphous Solid

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

JEE Main 2025 Helpline Numbers - Center Contact, Phone Number, Address

JEE Main Course 2025 - Important Updates and Details

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Types of Solutions

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

Thermodynamics Class 11 Notes: CBSE Chapter 5
