Question

In $1g$ of a solid there are $5 \times {10^{23}}$ atoms. If one electron is removed from energy of $0.01\% $ atoms of solid, the charge gained by the solid is:
(${\text{electronic charge = 1}}{\text{.6}} \times {\text{1}}{{\text{0}}^{19}}C$)
(A) $0.08C$
(B) $0.8C$
(C) $ - 0.08C$
(D) $ - 0.8C$

Answer 1

Hint: Electric Charge is defined as the amount of energy or the electrons that pass from one body to another by different methods like induction, conduction or by other specific methods. Charge is quantized which means that charge comes in integer multiples of the elementary charge ‘e’. So here we apply the formula for ‘quantisation of charge’.

Complete step by step solution:
First we need to find the number of electrons removed.
$n = \dfrac{{0.01}}{{100}} \times 5 \times {10^{21}}$
$ \Rightarrow n = 5 \times {10^{17}}$
Now we can find the total charge removed using the formula
$q = n \times e$
Where n is the number of electrons removed
E is the electronic charge.
$ \Rightarrow q = 5 \times {10^{17}} \times 1.6 \times {10^{ - 19}}$
$ \Rightarrow q = + 0.08C$

So the correct answer is option A

Additional Information: There are two types of charges, positive and negative charge. A proton has a charge of ‘+e’ while an electron has a charge of ‘-e’. Other than protons and electrons, positrons also carry charge in multiples of the electronic charges.
Electrons revolve around the nucleus in a fixed path.
One electron volt is the energy gained by the electrons when they travel through a potential difference of one volt

Note: Positive charge comes from having more number of protons than electrons while negative charge comes from having more electrons than the number of protons. Everybody on earth has a charge which is an integral multiple of ‘e’.