
In an astronomical telescope, the distance between the objective and the eyepiece is $d = 36cm$ and the final image is formed at infinity. The focal length ${f_o}$ of the objective and the focal length ${f_e}$ of the eyepiece are
(A) ${f_o} = 45cm,{f_e} = - 9cm$
(B) ${f_o} = 50cm,{f_e} = 20cm$
(C) ${f_o} = 7.2cm,{f_e} = 5cm$
(D) ${f_o} = 30cm,{f_e} = 6cm$
Answer
232.8k+ views
Hint: We use the formula for distance between objective lens and eyepiece. The formula for the distance between the two lenses is simply the sum of the focal lengths of both the lenses. The focal lengths of both the lenses are given in the options. We see which of the following focal lengths given in the options satisfies the formula for distance between the two lenses.
Formula used: Distance between the objective and eyepiece in an astronomical telescope is $d = {f_o} + {f_e}$
Where,
${f_e}$ is the focal length of eyepiece
${f_o}$ is the focal length of objective lens
$d$ is the distance between the two lenses
Complete step by step solution: From the question the distance between the eyepiece and the objective lens is
$d = 36cm$
In an astronomical telescope the distance between the two lenses is the sum of focal lengths of the lenses
$d = {f_o} + {f_e}$
From the given options the sum of focal lengths that gives us $d = 36cm$ is only option (A) and (D)
$d = 45 - 9 = 36cm$
$d = 30 + 6 = 36cm$
Hence option (A) ${f_o} = 45cm,{f_e} = - 9cm$ and (D) ${f_o} = 30cm,{f_e} = 6cm$ are the correct answers.
Additional information: An astronomical telescope having an objective with a long focal length and an eyepiece with a short focal length, usually used for observing celestial bodies like the moon and the planets in the solar system.
Note: In an astronomical telescope both the lenses are convex lenses. The light from the object at infinity gets refracted and forms an image at focal length of the objective lens. This image becomes the object for eye piece. The image of the eyepiece is magnified. This is why the distance between the two lenses is the sum of their focal lengths.
Formula used: Distance between the objective and eyepiece in an astronomical telescope is $d = {f_o} + {f_e}$
Where,
${f_e}$ is the focal length of eyepiece
${f_o}$ is the focal length of objective lens
$d$ is the distance between the two lenses
Complete step by step solution: From the question the distance between the eyepiece and the objective lens is
$d = 36cm$
In an astronomical telescope the distance between the two lenses is the sum of focal lengths of the lenses
$d = {f_o} + {f_e}$
From the given options the sum of focal lengths that gives us $d = 36cm$ is only option (A) and (D)
$d = 45 - 9 = 36cm$
$d = 30 + 6 = 36cm$
Hence option (A) ${f_o} = 45cm,{f_e} = - 9cm$ and (D) ${f_o} = 30cm,{f_e} = 6cm$ are the correct answers.
Additional information: An astronomical telescope having an objective with a long focal length and an eyepiece with a short focal length, usually used for observing celestial bodies like the moon and the planets in the solar system.
Note: In an astronomical telescope both the lenses are convex lenses. The light from the object at infinity gets refracted and forms an image at focal length of the objective lens. This image becomes the object for eye piece. The image of the eyepiece is magnified. This is why the distance between the two lenses is the sum of their focal lengths.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

