
$P = \dfrac{{{V^2}}}{R}$ is applied when
(1) Current is constant
(2) Potential difference is constant
(3) Resistance is constant
(4) None
Answer
232.8k+ views
Hint When in the circuit only resistors are present, then real power comes into action. With capacitors and inductors, reactive power comes into action. That is why in both cases the answers do not match.
Complete step by step solution
Power : Electrical Power in a circuit is the rate at which energy is produced or absorbed within a circuit. Any source of energy such as a voltage will produce or deliver power while the connected load absorbs it.
In simple words, If a current I flows through through a given element in your circuit, dropping voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage. Power is represented by P.
And the formula is given by :
$P = V \times I$
And we can use ohm’s law that is ( $V = I \times R$ ) and form the other relationship of this formula
$P = {I^2}R$
Or
$P = \dfrac{{{V^2}}}{R}$
When applied potential difference is constant, we use $P = \dfrac{{{V^2}}}{R}$
When current flowing is constant then we use $P = {I^2}R$
As resistance is always constant
We use $P = V \times I$ only when both the current as well as voltage is constant across the element or circuit.
The correct option is: Potential difference is constant.
Note All the formulas are correct or are just re-arrangements of each other using Ohm’s law. Before using the formula always observe which value is constant (voltage or current) as resistance is constant. So in the formula you use, your values used must be constant for the interval you want to calculate the power.
Complete step by step solution
Power : Electrical Power in a circuit is the rate at which energy is produced or absorbed within a circuit. Any source of energy such as a voltage will produce or deliver power while the connected load absorbs it.
In simple words, If a current I flows through through a given element in your circuit, dropping voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage. Power is represented by P.
And the formula is given by :
$P = V \times I$
And we can use ohm’s law that is ( $V = I \times R$ ) and form the other relationship of this formula
$P = {I^2}R$
Or
$P = \dfrac{{{V^2}}}{R}$
When applied potential difference is constant, we use $P = \dfrac{{{V^2}}}{R}$
When current flowing is constant then we use $P = {I^2}R$
As resistance is always constant
We use $P = V \times I$ only when both the current as well as voltage is constant across the element or circuit.
The correct option is: Potential difference is constant.
Note All the formulas are correct or are just re-arrangements of each other using Ohm’s law. Before using the formula always observe which value is constant (voltage or current) as resistance is constant. So in the formula you use, your values used must be constant for the interval you want to calculate the power.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

