
What is the RMS voltage?
A. \[\sqrt 2 \Delta {V_{\max }}\]
B. \[\Delta {V_{\max }}\]
C. \[\dfrac{{\Delta {V_{\max }}}}{{\sqrt 2 }}\]
D. \[\dfrac{{\Delta {V_{\max }}}}{2}\]
E. \[\dfrac{{\Delta {V_{\max }}}}{4}\]
Answer
232.8k+ views
Hint: In this question, we need to find the root mean square value of the voltage where RMS value is the effective value of the varying voltage and the current. RMS values are mathematical quantities used to compare both the alternating and the direct voltages or current. From the given five options we will find the correct value of RMS voltage.
Complete step by step solution:
In this question we need to write the value of the RMS voltage from the given options.
Root mean square is defined as the value of steady potential difference which generates the same amount of heat for a given resistance in a given time period as the AC voltage when maintained across the same resistance for the same amount of time. RMS is also a way of expressing an AC quantity of voltage and current functionally equivalent to DC.

Image: sinusoidal curve of alternating voltage.
The above figure shows the waveform of the Alternating voltage, where \[{V_{RMS}}\] is the RMS voltage and \[{V_{pk}}\] is the peak voltage. RMS voltage of a sinusoidal waveform is calculated by multiplying the peak voltage by \[0.7071\] or the peak voltage is divided by \[\sqrt 2 \], which is represented as,
\[{V_{RMS}} = \dfrac{1}{{\sqrt 2 }}{V_{pk}}\]
Where \[{V_{pk}}\] is the peak voltage
Therefore option C is the correct answer
Note:We know that in case of the Alternating current its average value is always equal to Zero because of the sinusoidal nature of the waveform, hence to measure the effective value of this quantity we use the RMS (root mean square) value.
Complete step by step solution:
In this question we need to write the value of the RMS voltage from the given options.
Root mean square is defined as the value of steady potential difference which generates the same amount of heat for a given resistance in a given time period as the AC voltage when maintained across the same resistance for the same amount of time. RMS is also a way of expressing an AC quantity of voltage and current functionally equivalent to DC.

Image: sinusoidal curve of alternating voltage.
The above figure shows the waveform of the Alternating voltage, where \[{V_{RMS}}\] is the RMS voltage and \[{V_{pk}}\] is the peak voltage. RMS voltage of a sinusoidal waveform is calculated by multiplying the peak voltage by \[0.7071\] or the peak voltage is divided by \[\sqrt 2 \], which is represented as,
\[{V_{RMS}} = \dfrac{1}{{\sqrt 2 }}{V_{pk}}\]
Where \[{V_{pk}}\] is the peak voltage
Therefore option C is the correct answer
Note:We know that in case of the Alternating current its average value is always equal to Zero because of the sinusoidal nature of the waveform, hence to measure the effective value of this quantity we use the RMS (root mean square) value.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

