Answer
Verified
112.5k+ views
Hint: Steel is an alloy of iron and other elements. Silicon steel is a ferritic alloy of iron and silicon. It is used to make transformers and motors. Silicon content of this steel improves magnetic softness and increases the electric resistivity.
Complete solution:
First let us know what silicon steel is.
As the name suggests, silicon steel is the ferritic alloy of silicon and iron. Silicon is a semiconductor material which is used to make the alloy as it promotes electrical resistivity and desired crystal orientations. Silicon also improves the acid resistance and thus increases the magnetic permeability.
Now, that we know about silicon steel, we first understand all the terms mentioned in the options and then answer the question.
The silicon in the silicon steel is added so as to improve the magnetic softness and increase the electrical resistivity.
When the current through the core flows in forward and reverse directions it results in magnetization and demagnetization of the core causing hysteresis loss. Hysteresis loss depends on the core materials and is the characteristic of magnetic permeability. Higher the permeability and lower the hysteresis loss, higher is the efficiency of the transformer/motor.
And as we know that using silicon steel increases the magnetic permeability, we can also say that using silicon steel reduces the hysteresis loss.
Therefore, we know that option (A) is the correct option. Still we need to check the other options too.
The circulating currents which are induced whenever a time varying flux passes and flows against the internal resistance of the core produces the eddy current loss. The silicon added in the silicon steel increases the electrical resistivity i.e. reduces the conductivity and thus reduces the eddy currents loss. To reduce the eddy current loss more magnetic cores are laminated.
Therefore, we now know that option (B) is also correct.
The electric current in the electrical devices produces heat which is termed as the copper loss. These copper losses can be reduced by lowering the grain resistance. Silicon in the silicon steel reduces the grain resistance of the transformer/motor and thus we can say that silicon steel reduces copper loss.
Therefore, option (C) is also right.
Since all the three options are correct, thus we know that all the options for the given question are correct.
Therefore, option (D), all of the above is the correct answer.
Note: The content of silicon in silicon steel is $3.2$ mass $\% $ and is the most common alloying material used with steel. It is mainly used in motors and transformers. It is necessary that we know the meaning of all the terms mentioned in the options. Also, we need to check all of the options to ensure that all the options are correct are not.
Complete solution:
First let us know what silicon steel is.
As the name suggests, silicon steel is the ferritic alloy of silicon and iron. Silicon is a semiconductor material which is used to make the alloy as it promotes electrical resistivity and desired crystal orientations. Silicon also improves the acid resistance and thus increases the magnetic permeability.
Now, that we know about silicon steel, we first understand all the terms mentioned in the options and then answer the question.
The silicon in the silicon steel is added so as to improve the magnetic softness and increase the electrical resistivity.
When the current through the core flows in forward and reverse directions it results in magnetization and demagnetization of the core causing hysteresis loss. Hysteresis loss depends on the core materials and is the characteristic of magnetic permeability. Higher the permeability and lower the hysteresis loss, higher is the efficiency of the transformer/motor.
And as we know that using silicon steel increases the magnetic permeability, we can also say that using silicon steel reduces the hysteresis loss.
Therefore, we know that option (A) is the correct option. Still we need to check the other options too.
The circulating currents which are induced whenever a time varying flux passes and flows against the internal resistance of the core produces the eddy current loss. The silicon added in the silicon steel increases the electrical resistivity i.e. reduces the conductivity and thus reduces the eddy currents loss. To reduce the eddy current loss more magnetic cores are laminated.
Therefore, we now know that option (B) is also correct.
The electric current in the electrical devices produces heat which is termed as the copper loss. These copper losses can be reduced by lowering the grain resistance. Silicon in the silicon steel reduces the grain resistance of the transformer/motor and thus we can say that silicon steel reduces copper loss.
Therefore, option (C) is also right.
Since all the three options are correct, thus we know that all the options for the given question are correct.
Therefore, option (D), all of the above is the correct answer.
Note: The content of silicon in silicon steel is $3.2$ mass $\% $ and is the most common alloying material used with steel. It is mainly used in motors and transformers. It is necessary that we know the meaning of all the terms mentioned in the options. Also, we need to check all of the options to ensure that all the options are correct are not.
Recently Updated Pages
Updated JEE Main Syllabus 2025 - Subject-wise Syllabus and More
JEE Main 2025 Exam Date: Check Important Dates and Schedule
JEE Main Admit Card 2025 Release Date and Time with Steps to Download
JEE Main 2025 City Intimation Slip: Downloading Link and Exam Centres
Uniform Acceleration - Definition, Equation, Examples, and FAQs
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Angle of Deviation in Prism - Important Formula with Solved Problems for JEE
Average and RMS Value for JEE Main
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Degree of Dissociation and Its Formula With Solved Example for JEE
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
Dual Nature of Radiation and Matter Class 12 Notes CBSE Physics Chapter 11 (Free PDF Download)
Diffraction of Light - Young’s Single Slit Experiment
JEE Main 2025: Derivation of Equation of Trajectory in Physics
Inductive Effect and Acidic Strength - Types, Relation and Applications for JEE
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking