Question

The period of oscillation of a vibration magnetometer depends on which of the following factors
A. \[I\] and \[M\] only
B. \[M\] and \[H\] only
C. \[I\] and \[H\] only
D. \[I,M\] and \[H\] only

Answer 1

Hint: Magnetic field strength and magnetic field intensity are other names for the same phenomenon. And the oscillation period refers to the length of time that it takes a particle to complete an one oscillation.

Formula used:
The time period of bar magnet is given by,
\[T = 2\pi \sqrt {\dfrac{I}{{MH}}} \]
Here, \[T\] is time period of oscillation of bar magnet, \[I\] is moment of inertia of the magnet about the axis of suspension, \[M\] is magnetic moment and \[H\] is magnetic field intensity of bar magnet or the external magnetic field.

Complete step by step solution:
In order for the model to be true, the net force exerted on the object at the pendulum's end must be commensurate to the displacement. As we know, the motion of a simple pendulum may be described by the basic harmonic motion and simple harmonic motion can also be used to describe molecular vibration.

The time period of bar magnet is given by,
\[T = 2\pi \sqrt {\dfrac{I}{{MH}}} \]
As a result, \[I,M\] and \[H\] only affects the vibration magnetometer's oscillation period.

Thus, the correct option is D.

Note: The magnetic field strength or magnetic field intensity is the ratio of the magnetomotive force necessary to create flux density per unit length of a particular material. The magnetic field of the planet is formed deep beneath the earth's core by the magnet's moment of inertia, which has a direct link with the oscillation period. The movement of liquid iron creates magnetic fields, which causes the Earth's core to generate an electric current.