NCERT Solutions for Class 6 Maths Chapter 1 - Knowing Our Numbers

Exercise 1.1

1. Fill in the blanks:

(a) 1 lakh = ____ ten thousand

(b) 1 million =____ hundred thousand

(c) 1 crore = ____ ten lakh

(d) 1 crore =____ million

(e) 1 million = ____ lakh

Ans:

(a) 1 lakh = \[10\] ten thousand

(b) 1 million = \[10\] hundred thousand

(c) 1 crore =  \[10\] ten lakh

(d) 1 crore = \[10\] million

(e) 1 million =  \[10\] lakh

2. Place commas correctly and write the numerals:

(a) Seventy-three lakh seventy-five thousand three hundred seven.

(b) Nine crore five lakh forty-one.

(c) Seven crore fifty-two lakh twenty-one thousand three hundred two.

(d) Fifty-eight million four hundred twenty-three thousand two hundred two.

(e) Twenty-three lakh thirty thousand ten.

Ans:

(a) Seventy-three lakh seventy-five thousand three hundred seven  \[=\text{ }73,75,307\text{ }\]

(b) Nine crore five lakh forty-one \[=\text{ }9,05,00,041\]

(c) Seven crore fifty-two lakh twenty-one thousand three hundred two \[=\text{ }7,52,21,302\text{ }\]

(d) Fifty-eight million four hundred twenty-three thousand two hundred two \[=\text{ }58,423,202\]

(e) Twenty-three lakh thirty thousand ten \[=\text{ }23,30,010\]

3. Insert commas suitable and write the names according to Indian system of numeration: 

(a) 87595762

(b) 8546283

(c) 99900046

(d) 98432701

Ans:

(a) \[8,75,95,762=\] Eight-crore seventy five lakh ninety-five thousand seven hundred sixty two

(b) \[85,46,283=\] Eighty-five lakh forty-six thousand two hundred eighty three

(c) \[9,99,00,046=\] Nine crore ninety-nine lakh forty six

(d) \[9,84,32,701=\] Nine crore eighty-four lakh thirty-two thousand seven hundred one

4. Insert commas suitable and write the names according to International system of numeration:

(a) 78921092

(b) 7452283

(c) 99985102

(d) 48049831

Ans:

(a) \[78,921,092=\] Seventy eight million nine hundred twenty one thousand ninety two

(b) \[7,452,283=\] Seven million four hundred fifty two thousand two hundred eighty three

(c) \[99,985,102=\] Ninety nine million nine hundred eighty five thousand one hundred two

(d) \[48,049,831=\] Forty eight million forty nine thousand eight hundred thirty one

Exercise 1.2

1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively \[\mathbf{1094},\mathbf{1812},\mathbf{2050}\text{ }\mathbf{and}\text{ }\mathbf{2751}\]. Find the total number of tickets sold on all the four days.

Ans:

Tickets sold of first day \[=\text{ }1,094\]

Tickets sold of second day \[=\text{ }1,812\]

Tickets sold of third day = 2,050

Tickets sold of fourth day \[=~2,751\]

Total tickets sold \[\begin{align} & =\text{ }1,094+1,812+2,050+2,751 \\ & =\text{ }7,707 \\ \end{align}\]

2. Shekhar is a famous cricket player. He has so far scored \[\mathbf{6980}\] runs in test matches. He wishes to complete \[\mathbf{10},\mathbf{000}\] runs. How many more runs does he need?

Ans:

Runs scored by Shekhar \[=\text{ }6980\]

Total number of runs he need \[\begin{align} & =\text{ }10,000-6980 \\ & =\text{ }3020 \\ \end{align}\].

3. In an election, the successful candidate registered \[\mathbf{5},\mathbf{77},\mathbf{500}\] votes and his nearest rival secured \[\mathbf{3},\mathbf{48},\mathbf{700}\] votes. By what margin did the successful candidate win the election?

Ans: Successful candidate secured votes \[=\text{ }5,77,500\]

Rival candidate secured votes \[=\text{ }3,48,700\]

Margin of votes \[\begin{align} & =\text{ }5,77,500-3,48,700 \\ & =\text{ }2,28,800 \\ \end{align}\]

4. Kirti Bookstore sold books worth \[\mathbf{2},\mathbf{85},\mathbf{891}\] in the first week of June and books worth \[\mathbf{4},\mathbf{00},\mathbf{768}\] in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Ans: Books sold in week one \[=\text{ }2,85,891\]

Books sold in week second \[=\text{ }4,00,768\]

Total sale \[=\text{ }4,00,768+2,85,891=6,86,659\]

Clearly, sale of second week is more than the first week sale

Difference \[\begin{align} & =\text{ }4,00,768-2,85,891 \\ & =\text{ }1,14,877 \\ \end{align}\]

5. Find the difference between the greatest and the least number that can be written using the digits \[\mathbf{6},\mathbf{2},\mathbf{7},\mathbf{4},\mathbf{3}\] each only once.

Ans: Largest five digit number  \[=76432\]

Smallest five-digit number  \[=\text{ }23467\]

Therefore, the difference between then  \[\begin{align} & =\text{ }76432-23467 \\ & =\text{ }52965 \\ \end{align}\]

6. A machine, on an average, manufactures \[\mathbf{2},\mathbf{825}\]screws a day. How many screws did it produce in the month of January \[\mathrm{2006}\]?

Ans:

Screws produced in one day \[=\text{ }2,825\]

Total Screws produced in \[31\] days \[\begin{align} & =\text{ }2,825\times 31\text{ } \\ & =\text{ }87,575 \\ \end{align}\]

Hence, the machine produced \[87,575\] screws in the month of January.

7. A merchant had \[\mathbf{78},\mathbf{592}\]with her. She placed an order for purchasing \[\mathbf{40}\] radio sets at \[\mathbf{1},\mathbf{200}\] each. How much money will remain with her after the purchase?

Ans:

Total money merchant had \[=\text{ }Rs.\text{ }78,592\]

Cost of one radio \[=\text{ }Rs.\text{ }1200\]

Cost of \[40\] radios \[=\text{ }1200\times 40=\text{ }Rs.\text{ }48,000\]

Money left\[\begin{align} & =\text{ }78,592-48,000 \\ & =\text{ }30,592 \\ \end{align}\]

8. A student multiplied \[\mathbf{7236}\text{ }\mathbf{by}\text{ }\mathbf{65}\] instead of multiplying \[\mathbf{by}\text{ }\mathbf{56}\]. By how much was his answer greater than the correct answer?

Ans:

Wrong answer \[\begin{align} & =\text{ }7236\times 65\text{ } \\ & =\text{ }470340 \\ \end{align}\]

Correct answer \[\begin{align} & =\text{ }7236\times 56\text{ } \\ & =\text{ }405216 \\ \end{align}\]

Difference in answers \[\begin{align} & =\text{ }470340-405216\text{ } \\ & =\text{ }65,124 \\ \end{align}\]

9. To stitch a shirt \[\mathbf{2}\text{ }\mathbf{m}\text{ }\mathbf{15}\text{ }\mathbf{cm}\] cloth is needed. Out of \[\mathbf{40}\text{ }\mathbf{m}\] cloth, how many shirts can be stitched and how much cloth will remain?

Ans:

Cloth required for stitch one shirt 

\[\begin{align} & =\text{ }2\text{ }m\text{ }15\text{ }cm \\ & =\text{ }2\times 100\text{ }cm+15\text{ }cm \\ & =215cm \\ \end{align}\]

Total length of cloth \[\begin{align} & =\text{ }40\text{ }m\text{ } \\ & =\text{ }40\times 100\text{ }cm \\ & =4000\text{ }cm \\ \end{align}\]

Number of shirts that can be stitched = \[\frac{4000}{215}\] \[215\overset{18}{\overline{\left){\begin{align} & 4000 \\ & \frac{-215}{\begin{align} & 1850 \\ & \frac{-1720}{130} \\ \end{align}} \\ \end{align}}\right.}}\]

Hence, \[18\] shirts can be stitched and \[130\text{ }cm\text{ }\left( 1\text{ }m\text{ }30\text{ }cm \right)\] cloth will be left.

10. Medicine is packed in boxes, each weighing \[\mathbf{4}\text{ }\mathbf{kg}\text{ }\mathbf{500}\text{ }\mathbf{g}\] . How many such boxes can be loaded in a can which cannot carry beyond \[\mathbf{800}\text{ }\mathbf{kg}\]?

Ans:

Weight of a box \[\begin{align} & =\text{ }4\text{ }kg\text{ }500\text{ }g\text{ } \\ & =\text{ }4500\text{ }g \\ \end{align}\]

Number of boxes \[=\text{ }\frac{800000}{4500}\]

\[4500\overset{177}{\overline{\left){\begin{align} & 800000 \\ & \frac{-4500}{\begin{align} & 35000 \\ & \frac{-31500}{\begin{align} & 35000 \\ & \frac{-31500}{3500} \\ \end{align}} \\ \end{align}} \\ \end{align}}\right.}}\]

Hence, \[177\] boxes can be loaded in the Van.

11. The distance between the school and the house of a student’s house is \[\mathbf{1}\text{ }\mathbf{km}\text{ }\mathbf{875}\text{ }\mathbf{m}\]. Every day she walks both ways. Find the total distance covered by her in six days.

Ans:

Distance between school and her house \[=\text{ }1875\text{ }m\]

Total distance covered \[\begin{align} & =\text{ }2\times 1875\text{ } \\ & =\text{ }3750\text{ }m \\ \end{align}\]

Distance covered in \[6\text{ }days\] \[\begin{align} & =\text{ }6\times 3750\text{ } \\ & =\text{ }22500\text{ }m \\ \end{align}\]

Thus, she covers \[22\text{ }km\text{ }500\text{ }m\] distance in \[6\text{ }days\]

12. A vessel has \[\mathbf{4}\text{ }\mathbf{liters}\text{ }\mathbf{and}\text{ }\mathbf{500}\text{ }\mathbf{ml}\] of curd. In how many glasses each of \[\mathbf{25}\text{ }\mathbf{ml}\] capacity, can it be filled?

Ans:

Capacity of vessel\[\begin{align} & =\text{ }4\text{ }liters\text{ }500\text{ }ml\text{ } \\ & =\text{ }4500\text{ }ml \\ \end{align}\]

Capacity of a glass \[=\text{ }25\text{ }ml\]

Number of glasses can be filled \[=\text{ }\frac{4500}{25}\] \[25\overset{180}{\overline{\left){\begin{align} & 4500 \\ & \frac{-25}{\begin{align} & 200 \\ & \frac{-200}{0} \\ \end{align}} \\ \end{align}}\right.}}\]

Therefore, \[180\] glasses are required.

Practice and Master the Concepts of the Chapter Knowing Our Numbers Class 6 Maths Chapter 1

1.1 Introduction

As students entered into the sixth standard, the NCERT solutions try to recall all their knowledge on numbers at the beginning of the chapter. As the students already learned different calculations like Asian, subtraction, multiplication, and division with the numbers, here, they may learn other ways to calculate or count the big numbers to express huge quantities.

1.2 Comparing Numbers

The Class 6 Maths Chapter 1 Solutions PDF contains the topic  “Knowing Our Numbers" to teach the students of grade 6 about comparing the larger numbers in different ways. Students can learn how to change the value of a number by shifting the digits, changing their places. Also, the subject experts explained the introduction of big numbers like 10,000 and 1,00,000. Not only numbers of students also taught how to find out the place value as well as keeping commas for the big numbers.

It ultimately deals with the reading and writing strategies of 5 - digit and 6 - digit numbers. So that the students can calculate more values while finding different problems as well as they are useful in their daily routine also.

• 1.2.1 How many numbers can you make?

• 1.2.2 Shifting of numbers.

• 1.2.3 Introducing 10,000.

• 1.2.4 Revisiting place value.

• 1.2.5 Introducing 1,00,000.

• 1.2.6 Larger numbers.

• 1.2.7 An aid in reading and writing large numbers.

1.3 Large Numbers in Practice

This part of Chapter 1 is important for Class 6 students to improve their thinking skills in math. It introduces the concept of estimation, teaching students how to estimate future events and plan for them. The chapter provides examples and scenarios to help students understand and practice estimating and forecasting. It also covers rounding numbers and basic arithmetic with large numbers.

• 1.3.1 Estimation

• 1.3.2 Estimating to the nearest tens by rounding off.

• 1.3.3 Estimating to the nearest hundreds by rounding off.

• 1.3.4 Estimating to the nearest thousands by rounding off.

• 1.3.5 Estimating outcomes of number situations.

• 1.3.6 To estimate sum or difference.

• 1.3.7 To estimate products.

1.4 Using Brackets

Introducing the usage of brackets is essential for 6th-grade students. The usage of brackets will occur mostly and two or more different things with one common point.so the students need to place the different things in a bracket, and the common thing will be outside the bracket. Students also learn the distribution of common things, which is outside the bracket to the different parts available within the brackets.

1.5 Roman Numerals

As the students knew the Hindu Arabic numeral system till primary classes, here they are introduced to the Roman numeric system, which is widely spread in the society. So, it is mandatory to teach them with several examples and perfect explanations. It can be easily done by NCERT Solutions Class 6 Maths Chapter 1.

Overview of Deleted Syllabus for CBSE Class 6 Maths Chapter 1 Knowing Our Numbers 2024-25

Exercises of Class 6 Maths Chapter 1 Knowing Our Numbers

Conclusion

The NCERT solutions for "Knowing Our Numbers" will help you understand place value, which is how the position of digits affects the value of a number. You will also learn how to compare and rank numbers, understand greater than, less than, and in-between figures, and work with larger numbers like thousands and crores. Additionally, you will learn how to write numbers using brackets and Roman numerals. In previous year question paper there were around 8-10 questions asked from the given topic.

Other Study Material for CBSE Class 6 Maths Chapter 1

Chapter wise NCERT Solutions for Class 6 Maths

Given below are the chapter-wise NCERT Solutions for Class 6 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.