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A biconvex lens of a transparent material of refractive index \[1.5\] is immersed in water of refractive index \[1.33\] . Will the lens behave as a converging or diverging lens? Give reason

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Hint:A bi convex lens is the simple lens which is the combination of two convex surfaces in spherical form, and both of the surfaces will have the same kind of radius of curvature. And it will act as a converging lens.

Complete step by step solution:A biconvex lens also called convex-convex lens will act as a converging lens because the material’s refractive index will be higher than that of the air.
Here it is given that the refractive inductance of the material is equal to \[1.5\] .
The term refractive index of a material refers to the ratio of the velocity of light in the vacuum to the velocity of light when the light is passing through that particular material. And it is a dimensionless quantity.
We know that, when a biconvex lens acts as a converging lens, it should be placed in another medium which has a lower refractive index than that particular material.
In the question it is given that the lens is immersed in water of refractive inductance\[1.33\] . And the refractive index of the material of the biconvex lens is \[1.5\]
Here, the value of the refractive index of the material of the biconvex is higher than the refractive index of water. So the biconvex lens will act as a converging lens when the lens is immersed in water.

Note:Refractive index is a term used in optics that describes characteristics of a material as how fast can the light pass through the material. Refractive index determines how much bend is happening to the light when the light passes through that material. It is also known as refraction index or index of refraction.