Answer
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Hint: The force acting on the ball immediately after it is dropped is the gravitational force which accelerates the ball by acceleration due to gravity, g.
The time and velocity of the ball at any point can be determined using equations of motion.
Formula used: For a body under free fall, ${{v}^{2}}=2gh$ ; $t=\dfrac{v}{g}$
Complete step by step answer:
When an object is dropped from a height, it moves under the sole influence of gravitational force due to earth. This motion of objects under the influence of gravity is known as free fall. The object accelerates with a constant acceleration due to gravity.
The velocity of a freely falling body at any position is given by
${{v}^{2}}-{{u}^{2}}=2gh$
Where
$h=$ Vertical distance covered
$u=$ Initial velocity
$g=$ Acceleration due to gravity $\approx 10m{{s}^{-2}}$
Here the object is dropped so the initial velocity of the object is zero. Therefore the equation becomes
${{v}^{2}}=2gh$
Since, the ball is dropped from height 20 m, the vertical distance travelled by ball on reaching the ground is the height from which it is dropped i.e. 20 m. Therefore,
${{v}^{2}}=2\times 10\times 20=400\,{{m}^{2}}/{{s}^{2}}$
The velocity of ball on reaching the ground is 20 m/s
Velocity of a freely falling body is related to its time as
$v=u+gt$
Since, u = 0, we have
$v=gt\Rightarrow t=\dfrac{v}{g}$
Therefore,
$t=\dfrac{20}{10}=2\,s$
$\Rightarrow v=\sqrt{400}=20m/s$
Time taken by the ball to reach the ground is 2 s.
So, the correct answer is “Option A and C”.
Note: In such types of questions, sometimes students forget to consider the initial velocity of the object during free fall as zero. So here initial velocity won’t affect but that might mislead the concept.
When an object is dropped from a height, it moves under the sole influence of gravitational force due to earth.
The time and velocity of the ball at any point can be determined using equations of motion.
Formula used: For a body under free fall, ${{v}^{2}}=2gh$ ; $t=\dfrac{v}{g}$
Complete step by step answer:
When an object is dropped from a height, it moves under the sole influence of gravitational force due to earth. This motion of objects under the influence of gravity is known as free fall. The object accelerates with a constant acceleration due to gravity.
The velocity of a freely falling body at any position is given by
${{v}^{2}}-{{u}^{2}}=2gh$
Where
$h=$ Vertical distance covered
$u=$ Initial velocity
$g=$ Acceleration due to gravity $\approx 10m{{s}^{-2}}$
Here the object is dropped so the initial velocity of the object is zero. Therefore the equation becomes
${{v}^{2}}=2gh$
Since, the ball is dropped from height 20 m, the vertical distance travelled by ball on reaching the ground is the height from which it is dropped i.e. 20 m. Therefore,
${{v}^{2}}=2\times 10\times 20=400\,{{m}^{2}}/{{s}^{2}}$
The velocity of ball on reaching the ground is 20 m/s
Velocity of a freely falling body is related to its time as
$v=u+gt$
Since, u = 0, we have
$v=gt\Rightarrow t=\dfrac{v}{g}$
Therefore,
$t=\dfrac{20}{10}=2\,s$
$\Rightarrow v=\sqrt{400}=20m/s$
Time taken by the ball to reach the ground is 2 s.
So, the correct answer is “Option A and C”.
Note: In such types of questions, sometimes students forget to consider the initial velocity of the object during free fall as zero. So here initial velocity won’t affect but that might mislead the concept.
When an object is dropped from a height, it moves under the sole influence of gravitational force due to earth.
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