
A box contains 4 bags of sugar. The total mass of all the 4 bags is 7kg. What is the mass of each bag in grams?
(a) 1.75gms
(b) 17.50gms
(c) 175gms
(d) 1750gms
Answer
493.5k+ views
Hint: We will first assume the mass of each bag to be some variable say x. Then, we are given that the mass of 4 bags is 7kg. So, we have an equation as $4x=7$ . On solving this answer, we will get an answer in kg. So, we will convert it into grams using the rule $1kg=1000gms$ . Thus, we will then get the answer.
Complete step-by-step answer:
Here, we will assume that the weight of each bag of sugar is some random variable x. Now, we are given that the total mass of 4 bags is equal to 7kg. So, we can write in mathematical form as
$x+x+x+x=7kg$
$4x=7$
On dividing it with 4 on both sides, we will get
$x=\dfrac{7}{4}=1.75kg$
Now, we will convert it into grams as our options given in the question are in grams units. So, we will use the rule of conversion as $1kg=1000gms$ .
On using unitary method, we will get as
$\begin{align}
& 1kg=1000gms \\
& 1.75kg=? \\
\end{align}$
On solving, we get
$=100\times 1.75gms$
$=1750gms$
Thus, the mass of each bag is 1750gms.
Hence, option (d) is the correct answer.
Note: Another way to solve this problem is by option method. We can take each option and add it 4 times as there are4 bags of sugar. Then on getting answers in grams we will convert it into kilogram units using the rule $1kg=1000gms$ . Then we will see whether it is equal to 7kg or not.
So, taking option (a): 1.75gms. On adding 4 times, we will get $1.75+1.75+1.75+1.75=7gms$ . Now, converting this into kg, we will get as
$\begin{align}
& 1kg=1000gms \\
& ?=7gms \\
\end{align}$
On solving, we will get an answer as $\dfrac{7\times 1}{1000}=0.007kg$ . So 0.007 is not the same as 7kg. Thus, this is not the correct answer. By doing this way we will have the same answer i.e. option (d).
Complete step-by-step answer:
Here, we will assume that the weight of each bag of sugar is some random variable x. Now, we are given that the total mass of 4 bags is equal to 7kg. So, we can write in mathematical form as
$x+x+x+x=7kg$
$4x=7$
On dividing it with 4 on both sides, we will get
$x=\dfrac{7}{4}=1.75kg$
Now, we will convert it into grams as our options given in the question are in grams units. So, we will use the rule of conversion as $1kg=1000gms$ .
On using unitary method, we will get as
$\begin{align}
& 1kg=1000gms \\
& 1.75kg=? \\
\end{align}$
On solving, we get
$=100\times 1.75gms$
$=1750gms$
Thus, the mass of each bag is 1750gms.
Hence, option (d) is the correct answer.
Note: Another way to solve this problem is by option method. We can take each option and add it 4 times as there are4 bags of sugar. Then on getting answers in grams we will convert it into kilogram units using the rule $1kg=1000gms$ . Then we will see whether it is equal to 7kg or not.
So, taking option (a): 1.75gms. On adding 4 times, we will get $1.75+1.75+1.75+1.75=7gms$ . Now, converting this into kg, we will get as
$\begin{align}
& 1kg=1000gms \\
& ?=7gms \\
\end{align}$
On solving, we will get an answer as $\dfrac{7\times 1}{1000}=0.007kg$ . So 0.007 is not the same as 7kg. Thus, this is not the correct answer. By doing this way we will have the same answer i.e. option (d).
Recently Updated Pages
How do you factor x2 + x 20 0 class 9 maths CBSE

How do you solve y6x and 2x+3y20 using substitutio class 9 maths CBSE

Chipko movement originated in Gopeshwar in A 1953 B class 9 biology CBSE

The adjacent sides in the parallelogram are supplementary class 9 maths CBSE

The compound used in plastic industry is A Vinyl acetate class 9 chemistry CBSE

How do you solve for y in 2left y dfrac12 right 4left class 9 maths CBSE

Trending doubts
Write the difference between soap and detergent class 10 chemistry CBSE

When was Shivaji born A 1632 B 1627 C 1678 D 1634 class 10 social science CBSE

a Why did Mendel choose pea plants for his experiments class 10 biology CBSE

State and explain Ohms law class 10 physics CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Differentiate between Food chain and Food web class 10 biology CBSE
