Answer
Verified
396k+ views
Hint: Heat is a form of energy. As a result of temperature difference, heat energy is transferred from one body to another body .Heat flows from hotter body to cooler body. Temperature is the measure of the amount of heat energy present in a body.SI unit of heat is joule (J) and calorie is also used as the unit of heat.
Complete step-by-step solution:
Work is a form of heat. Work and energy are directly proportional to each other and energy can be converted into different forms. Energy which cannot be created nor destroyed but it can be transformed .SI units of energy are also joules so don’t confuse work and energy.
In SI unit mass is measured in kilogram (kg), length is measured in meter(m) and time is measured in second (s). So ${{M}_{1}}=1kg$ , ${{L}_{1}}=1m$ and ${{T}_{_{1}}}=1s$.
In the new system mass is measured in ($\alpha kg$), length is measured in ($\beta m$) and time is measured in ($\gamma s$). So ${{M}_{2}}=\alpha kg$ , ${{L}_{2}}=\beta m$ and ${{T}_{_{2}}}=\gamma s$.
By the standard unit conversion formula
$\dfrac{Given Unit({{n}_{2}})}{Newunit({{n}_{1}})}={{\left[ \dfrac{{{M}_{1}}}{{{M}_{2}}} \right]}^{x}}{{\left[ \dfrac{{{L}_{1}}}{{{L}_{2}}} \right]}^{y}}{{\left[ \dfrac{{{T}_{1}}}{{{T}_{2}}} \right]}^{z}}$
$1cal=4.2kg{{m}^{2}}{{s}^{-2}}$
So ${{n}_{1}}=4.2$
Dimensional formula of heat is $[{{M}^{1}}{{L}^{2}}{{T}^{-2}}]$ is compared with $[{{M}^{x}}{{L}^{y}}{{T}^{z}}]$ then we get the values of
X=1, y=2 and z=-2
After substituting
\[\begin{align}
& {{n}_{2}}={{n}_{1}}{{\left[ \dfrac{{{M}_{1}}}{{{M}_{2}}} \right]}^{x}}{{\left[ \dfrac{{{L}_{1}}}{{{L}_{2}}} \right]}^{y}}{{\left[ \dfrac{{{T}_{1}}}{{{T}_{2}}} \right]}^{z}} \\
& {{n}_{2}}=4.2{{\left[ \dfrac{1kg}{\alpha kg} \right]}^{1}}{{\left[ \dfrac{1m}{\beta m} \right]}^{2}}{{\left[ \dfrac{1s}{1s} \right]}^{-2}} \\
& {{n}_{2}}=4.2{{\alpha }^{1}}{{\beta }^{2}}{{\gamma }^{-2}} \\
\end{align}\]
caloric has a magnitude $4.2{{\alpha }^{-1}}{{\beta }^{-2}}{{\gamma }^{2}}$ in terms of the new units is obtained.
Note:Student’s heat transfer is a branch of thermal engineering in that we are going to study generation, heat transfer and conversion. Heat transfer is the flow of heat due a temperature difference between the bodies. There are three mechanisms of heat transfer and they are conduction, convection and radiation.
Complete step-by-step solution:
Work is a form of heat. Work and energy are directly proportional to each other and energy can be converted into different forms. Energy which cannot be created nor destroyed but it can be transformed .SI units of energy are also joules so don’t confuse work and energy.
In SI unit mass is measured in kilogram (kg), length is measured in meter(m) and time is measured in second (s). So ${{M}_{1}}=1kg$ , ${{L}_{1}}=1m$ and ${{T}_{_{1}}}=1s$.
In the new system mass is measured in ($\alpha kg$), length is measured in ($\beta m$) and time is measured in ($\gamma s$). So ${{M}_{2}}=\alpha kg$ , ${{L}_{2}}=\beta m$ and ${{T}_{_{2}}}=\gamma s$.
By the standard unit conversion formula
$\dfrac{Given Unit({{n}_{2}})}{Newunit({{n}_{1}})}={{\left[ \dfrac{{{M}_{1}}}{{{M}_{2}}} \right]}^{x}}{{\left[ \dfrac{{{L}_{1}}}{{{L}_{2}}} \right]}^{y}}{{\left[ \dfrac{{{T}_{1}}}{{{T}_{2}}} \right]}^{z}}$
$1cal=4.2kg{{m}^{2}}{{s}^{-2}}$
So ${{n}_{1}}=4.2$
Dimensional formula of heat is $[{{M}^{1}}{{L}^{2}}{{T}^{-2}}]$ is compared with $[{{M}^{x}}{{L}^{y}}{{T}^{z}}]$ then we get the values of
X=1, y=2 and z=-2
After substituting
\[\begin{align}
& {{n}_{2}}={{n}_{1}}{{\left[ \dfrac{{{M}_{1}}}{{{M}_{2}}} \right]}^{x}}{{\left[ \dfrac{{{L}_{1}}}{{{L}_{2}}} \right]}^{y}}{{\left[ \dfrac{{{T}_{1}}}{{{T}_{2}}} \right]}^{z}} \\
& {{n}_{2}}=4.2{{\left[ \dfrac{1kg}{\alpha kg} \right]}^{1}}{{\left[ \dfrac{1m}{\beta m} \right]}^{2}}{{\left[ \dfrac{1s}{1s} \right]}^{-2}} \\
& {{n}_{2}}=4.2{{\alpha }^{1}}{{\beta }^{2}}{{\gamma }^{-2}} \\
\end{align}\]
caloric has a magnitude $4.2{{\alpha }^{-1}}{{\beta }^{-2}}{{\gamma }^{2}}$ in terms of the new units is obtained.
Note:Student’s heat transfer is a branch of thermal engineering in that we are going to study generation, heat transfer and conversion. Heat transfer is the flow of heat due a temperature difference between the bodies. There are three mechanisms of heat transfer and they are conduction, convection and radiation.
Watch videos on
A calorie is a unit of heat (energy in transit) and it equals about 4.2J where \[1J=1kg{{m}^{2}}{{s}^{-2}}\]. Suppose we employ a system of units in which the unit of mass equals $\alpha kg$ ,The unit of length equals $\beta m$ , the unit of time is $\gamma s$.show that a caloric has a magnitude $4.2{{\alpha }^{-1}}{{\beta }^{-2}}{{\gamma }^{2}}$ in terms of the new units.
NCERT EXERCISE 1.3 | NCERT Solution for Class 11 Physics Chapter 1 | Units and Measurement NCERT
Subscribe
Share
likes
7.4K Views
1 year ago
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE