Answer
Verified
428.4k+ views
Hint: Calculate the cost price of 50 kg of apples. Then calculate the loss accrued using percentage.
Complete step by step solution:
It is given that , A fruit seller bought $80\,kg $ of apples at ₹ $12.50$ per kg.
After that he sold $50$ kg of it at a loss of $10$ per cent.
So, we are asked to calculate at what price per kg should he sell the remaining apple so as to gain $20$ per cent on the whole.
According to question,
$ $Cost of $1\,kg$ apple= ₹ $12.50$
So, Cost of $50\,kg$ apple = ₹ $12.50 \times 50$
So, Cost of $50\,kg$ apple = ₹ $625$
Now loss on $50$ kg apples $ = 10\% .$
Let the selling price on $50\,kg$ be $'x'.$
Then using formula to get $'x'$
$\dfrac{{C.P - S.P}}{{C.P}} \times 100 = $Loss % on $50\,kg$
Putting values in formula.
$ \Rightarrow \dfrac{{625 - x}}{{625}} \times 100 = 10$
$625 - x = \dfrac{{10 \times 258}}{4}$
$625 - x = \dfrac{{125}}{2} = 62.5$
$x = - 62.5 + 625$
$\therefore x = 562.5$ ₹
Selling price on \[50kg\] to loss $10\% $
Now for remaining $30kg$ apple out of $80\,kg.$
Cost price of $1\,kg$ apple$ = 12.50$ ₹
Cost price of $30\,kg $ apple $ = 12.50 \times 30$
$ = 375$ ₹
Let selling price of $30\,kg$ apple be $y$
So, Total cost price of $30\,kg$ apple=$625 + 375$ ₹
$ = $₹ $1000$
And total selling price of $80\,kg$ apple$ = $₹ $562.5 + y$
Hence the required profit on the whole$\% = $(Total selling price-Total cost price)×100/(Total Cost Price) = gain % on $80\,kg.$
Then put value in this formula
$ \Rightarrow \dfrac{{562.5 + y - 1000}}{{1000}} \times 100 = 20$
$562.5 + y - 1000 = 200$
$y = 1200 - 562.5$
$y = 637.5$ ₹
So, the selling price of $30kg\, Apple = y $
$ = 637.5$ ₹
Selling price of $ 1kg $ Apple $ = \dfrac{{637.5}}{{30}}$
$= ₹ 21.25 $ .
Note:
We need to understand that he was at a loss for the sale of the first 50 kg apples. So he needed to recover that loss and the new profit, both, from the sale of remaining 30 kg apples. So, the total investment and the total profit must have been taken out from the sale of the remaining 30 kg apples.
Complete step by step solution:
It is given that , A fruit seller bought $80\,kg $ of apples at ₹ $12.50$ per kg.
After that he sold $50$ kg of it at a loss of $10$ per cent.
So, we are asked to calculate at what price per kg should he sell the remaining apple so as to gain $20$ per cent on the whole.
According to question,
$ $Cost of $1\,kg$ apple= ₹ $12.50$
So, Cost of $50\,kg$ apple = ₹ $12.50 \times 50$
So, Cost of $50\,kg$ apple = ₹ $625$
Now loss on $50$ kg apples $ = 10\% .$
Let the selling price on $50\,kg$ be $'x'.$
Then using formula to get $'x'$
$\dfrac{{C.P - S.P}}{{C.P}} \times 100 = $Loss % on $50\,kg$
Putting values in formula.
$ \Rightarrow \dfrac{{625 - x}}{{625}} \times 100 = 10$
$625 - x = \dfrac{{10 \times 258}}{4}$
$625 - x = \dfrac{{125}}{2} = 62.5$
$x = - 62.5 + 625$
$\therefore x = 562.5$ ₹
Selling price on \[50kg\] to loss $10\% $
Now for remaining $30kg$ apple out of $80\,kg.$
Cost price of $1\,kg$ apple$ = 12.50$ ₹
Cost price of $30\,kg $ apple $ = 12.50 \times 30$
$ = 375$ ₹
Let selling price of $30\,kg$ apple be $y$
So, Total cost price of $30\,kg$ apple=$625 + 375$ ₹
$ = $₹ $1000$
And total selling price of $80\,kg$ apple$ = $₹ $562.5 + y$
Hence the required profit on the whole$\% = $(Total selling price-Total cost price)×100/(Total Cost Price) = gain % on $80\,kg.$
Then put value in this formula
$ \Rightarrow \dfrac{{562.5 + y - 1000}}{{1000}} \times 100 = 20$
$562.5 + y - 1000 = 200$
$y = 1200 - 562.5$
$y = 637.5$ ₹
So, the selling price of $30kg\, Apple = y $
$ = 637.5$ ₹
Selling price of $ 1kg $ Apple $ = \dfrac{{637.5}}{{30}}$
$= ₹ 21.25 $ .
Note:
We need to understand that he was at a loss for the sale of the first 50 kg apples. So he needed to recover that loss and the new profit, both, from the sale of remaining 30 kg apples. So, the total investment and the total profit must have been taken out from the sale of the remaining 30 kg apples.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write the differences between monocot plants and dicot class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE