
A hydraulic lift at a service station can lift cars with a mass of . The area of the cross section of the piston carrying the load is . What pressure does the smaller piston experience? Take ?
Answer
486.6k+ views
Hint: The pressure due to applied force is the ratio of magnitude of force and the area of the cross section on which the force is applied.
Complete step by step answer:
According to Newton’s law of gravitation, the gravitational force exerted on the car of mass m is given by the equation,
Here, g is acceleration due to gravity.
The pressure exerted on the smaller piston of the hydraulic lift is the ratio of force exerted on the car to the area of the cross section of the smaller piston.
Therefore,
Substitute for m, for g and for A in the above equation.
Therefore, the pressure experienced by the smaller piston is .
Note:
The weight of the object is the gravitational force exerted on the object. Sometimes students misunderstand between the mass and the weight of the object. 3500 kg is the mass of the car and not the weight. Therefore, you need to calculate the weight of the car by multiplying its mass by the acceleration due to gravity. Also, , therefore, .
Complete step by step answer:
According to Newton’s law of gravitation, the gravitational force exerted on the car of mass m is given by the equation,
Here, g is acceleration due to gravity.
The pressure exerted on the smaller piston of the hydraulic lift is the ratio of force exerted on the car to the area of the cross section of the smaller piston.
Therefore,
Substitute
Therefore, the pressure experienced by the smaller piston is
Note:
The weight of the object is the gravitational force exerted on the object. Sometimes students misunderstand between the mass and the weight of the object. 3500 kg is the mass of the car and not the weight. Therefore, you need to calculate the weight of the car by multiplying its mass by the acceleration due to gravity. Also,
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
State and prove Bernoullis theorem class 11 physics CBSE

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

Write the differences between monocot plants and dicot class 11 biology CBSE

Who built the Grand Trunk Road AChandragupta Maurya class 11 social science CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

State the laws of reflection of light
