Answer
427.8k+ views
Hint: The current carrying coil develops a magnetic field around the coil. The magnetic field is always perpendicular to the direction of current flow from the right-hand thumb rule. The area of the coil determines the magnetic field strength at a point.
Complete answer:
Let us consider the given coil as the source of the magnetic field. The magnetic moment is a quantity which determines the magnetic strength and its orientation with respect to the object that develops the magnetic field, here the coil. The magnetic moment is given by: \[\mu =N(I\times A)\], where N is the number of turns in the coil, I is the current through the coil and A is the area of the coil.
So, let us find the area of the given coil. It consists of four semicircles each of radius, \[r=\dfrac{a}{2}\] and a square of side a.
i.e., The area of the coil is given by,
\[\begin{align}
& A=4\times \dfrac{\pi {{\left( \dfrac{a}{2} \right)}^{2}}}{2}+{{a}^{2}} \\
& A=2\pi \dfrac{{{a}^{2}}}{4}+{{a}^{2}} \\
& A={{a}^{2}}(\dfrac{\pi }{2}+1) \\
\end{align}\]
Now, let us find the magnetic moment of the coil,
\[\begin{align}
& \mu =N(I\times A) \\
& \mu =NIA\sin \theta \\
& but\text{ }\theta ={{90}^{0}} \\
\end{align}\]
The current and area are perpendicular to each other,
So, \[\sin \theta =1\]
The magnetic moment is,
\[\begin{align}
& \mu =NIA \\
& \mu =1\times I{{a}^{2}}(\dfrac{\pi }{2}+1) \\
& \therefore \mu =I{{a}^{2}}(\dfrac{\pi }{2}+1) \\
\end{align}\]
The direction of moment is perpendicular to both current and area, i.e., it is along \[\widehat{k}\]
Therefore, the magnetic moment is given by:
\[\mu \text{=(}\dfrac{\pi }{2}+1){{\text{a}}^{2}}I\widehat{k}\]
The correct answer is option B.
Note:
Magnetic dipole moment is the elaborated name given to the magnetic moments. In electrostatics, a pair of equal and opposite charges constitute a dipole, whereas in magnetostatics, there is no chance of monopoles. Magnetism is always dipole in nature.
The magnetic moment of an electron has a special unit known as Bohr Magneton (BM).
Complete answer:
Let us consider the given coil as the source of the magnetic field. The magnetic moment is a quantity which determines the magnetic strength and its orientation with respect to the object that develops the magnetic field, here the coil. The magnetic moment is given by: \[\mu =N(I\times A)\], where N is the number of turns in the coil, I is the current through the coil and A is the area of the coil.
![seo images](https://www.vedantu.com/question-sets/a7e9e301-c6cc-4544-bedd-146765ce80857213761894013623931.png)
So, let us find the area of the given coil. It consists of four semicircles each of radius, \[r=\dfrac{a}{2}\] and a square of side a.
i.e., The area of the coil is given by,
\[\begin{align}
& A=4\times \dfrac{\pi {{\left( \dfrac{a}{2} \right)}^{2}}}{2}+{{a}^{2}} \\
& A=2\pi \dfrac{{{a}^{2}}}{4}+{{a}^{2}} \\
& A={{a}^{2}}(\dfrac{\pi }{2}+1) \\
\end{align}\]
Now, let us find the magnetic moment of the coil,
\[\begin{align}
& \mu =N(I\times A) \\
& \mu =NIA\sin \theta \\
& but\text{ }\theta ={{90}^{0}} \\
\end{align}\]
The current and area are perpendicular to each other,
So, \[\sin \theta =1\]
The magnetic moment is,
\[\begin{align}
& \mu =NIA \\
& \mu =1\times I{{a}^{2}}(\dfrac{\pi }{2}+1) \\
& \therefore \mu =I{{a}^{2}}(\dfrac{\pi }{2}+1) \\
\end{align}\]
The direction of moment is perpendicular to both current and area, i.e., it is along \[\widehat{k}\]
Therefore, the magnetic moment is given by:
\[\mu \text{=(}\dfrac{\pi }{2}+1){{\text{a}}^{2}}I\widehat{k}\]
The correct answer is option B.
Note:
Magnetic dipole moment is the elaborated name given to the magnetic moments. In electrostatics, a pair of equal and opposite charges constitute a dipole, whereas in magnetostatics, there is no chance of monopoles. Magnetism is always dipole in nature.
The magnetic moment of an electron has a special unit known as Bohr Magneton (BM).
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