Answer
Verified
469.2k+ views
Hint: The opposition offered by the inductor in an A.C circuit to flow the A.C current is known as inductive reactance. The working principle of ammeter is that it should have low inductive reactance and resistivity.
Complete step by step answer:
We can convert a galvanometer to an ammeter by connecting the galvanometer in parallel to a low resistance, which is known as a shunt. The value of the shunt is adjusted so that the maximum current flow through the shunt. Thus, the galvanometer is converted to an ammeter and now can easily measure heavy currents without being fully deflected. And the conversion of the galvanometer into the ammeter is given in the circuit diagram.
To find the current resistivity of the galvanometer:
$K = \dfrac{E}{{\left( {P + Q} \right).G}}\left( {\dfrac{P}{d}} \right)\dfrac{{Amp}}{{div}}$
Where, $K$is the current resistivity, $G$is the galvanometer, $P,Q$is the resistance boxes.
Thus, from the above explanation, we can conclude that option (B)- introducing a shunt resistance of small value in parallel, is the correct answer.
Additional information:
An ammeter is a device to measure current and has negligible resistance, that is connected in series with the test resistor. A galvanometer is a device that can determine the presence, direction, and strength of an electric current and voltage in a circuit.
A galvanometer is extremely sensitive to high currents and to measure heavy currents, a galvanometer is always converted into an ammeter. A resistor that has a small resistance connected in parallel with the coil in an ammeter. This resistor is called a shunt. A shunt allows electric current to move around another point of the circuit by breaking it and shifting it to another point in the circuit by creating a low resistance path. The sensitivity of a galvanometer can be expressed as a ratio of change in deflection of the galvanometer and change in value. To measure currents, we need to connect the galvanometer in series and since this setup will have large resistance, it will undoubtedly change the current in the circuit. So, to maintain the level of current a small resistance, is needed to be connected in parallel.
Note:
Remember that the small resistor, that is the shunt, needs to be connected in parallel with the galvanometer to reduce the resistance. This is because when resistances are connected in parallel their average resistance is low and when connected in series, the average resistance is higher.`B
Complete step by step answer:
We can convert a galvanometer to an ammeter by connecting the galvanometer in parallel to a low resistance, which is known as a shunt. The value of the shunt is adjusted so that the maximum current flow through the shunt. Thus, the galvanometer is converted to an ammeter and now can easily measure heavy currents without being fully deflected. And the conversion of the galvanometer into the ammeter is given in the circuit diagram.
To find the current resistivity of the galvanometer:
$K = \dfrac{E}{{\left( {P + Q} \right).G}}\left( {\dfrac{P}{d}} \right)\dfrac{{Amp}}{{div}}$
Where, $K$is the current resistivity, $G$is the galvanometer, $P,Q$is the resistance boxes.
Thus, from the above explanation, we can conclude that option (B)- introducing a shunt resistance of small value in parallel, is the correct answer.
Additional information:
An ammeter is a device to measure current and has negligible resistance, that is connected in series with the test resistor. A galvanometer is a device that can determine the presence, direction, and strength of an electric current and voltage in a circuit.
A galvanometer is extremely sensitive to high currents and to measure heavy currents, a galvanometer is always converted into an ammeter. A resistor that has a small resistance connected in parallel with the coil in an ammeter. This resistor is called a shunt. A shunt allows electric current to move around another point of the circuit by breaking it and shifting it to another point in the circuit by creating a low resistance path. The sensitivity of a galvanometer can be expressed as a ratio of change in deflection of the galvanometer and change in value. To measure currents, we need to connect the galvanometer in series and since this setup will have large resistance, it will undoubtedly change the current in the circuit. So, to maintain the level of current a small resistance, is needed to be connected in parallel.
Note:
Remember that the small resistor, that is the shunt, needs to be connected in parallel with the galvanometer to reduce the resistance. This is because when resistances are connected in parallel their average resistance is low and when connected in series, the average resistance is higher.`B
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
Which is the longest day and shortest night in the class 11 sst CBSE
What is the definite integral of zero a constant b class 12 maths CBSE
Name five important trees found in the tropical evergreen class 10 social studies CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE