Question

A part of monthly expenses of a family on milk is fixed which is Rs. 700 and remaining varies with quantity of milk taken extra at the rate of \[Rs.{\text{ }}25{\text{ }}per{\text{ }}litre\]. Taking the quantity of milk required extra as $x$ litre and total expenditure on milk Rs. $y$, write a linear equation representing the above information.

Answer 1

Hint:Here, we have to form linear equation based on given information in the question , that the variables with power of 1 the variables provided are quantity of milk required extra as ‘$x$’ litre and total expenditure on milk Rs. ‘$y$’. Basically, it’s a question based on the formation of linear equations as per question. Also, a formula applied here is -
Remaining expenditure = (cost of milk per litre) $ \times $(quantity of milk taken extra)

Complete step-by-step answer:
As per the question it is given that the quantity of milk required extra as ‘$x$’ litre and total expenditure on milk Rs. ‘$y$’.
According to the question it is given that a part of monthly expenses of a family on a milk is fixed = Rs. 700.
Now, The Remaining expenditure = $ = 25 \times $(quantity of milk taken extra)
$ = 25 \times x = 25x$
Now the total expenditure y $ = 700 + 25x$
$ \Rightarrow y = 700 + 25x$
So the required linear equation which represents the above information is $y = 700 + 25x$

Note:As this question is completely based on formation of a linear equation, we should have knowledge of what it is actually. By definition, an equation is a mathematical statement in such a form that two different mathematical expressions (having some unknown term) are equal to each other.
In this type of problem of forming linear equations of different variables. Firstly, the variables are to be chosen from the problem. Then, the independent variable should be used to take the form of the dependent variable from given information.