Question

A ray of light is moving from a rare to a denser medium and strikes a plane mirror at ${90}^{\circ }$ to the direction of the ray as shown in the diagram.
(i). Copy the diagram and mark the arrows to show the path of the ray of the light after it is reflected from the mirror.
(ii). Name the principle you have used to mark the arrow the direction of the ray.

Answer 1

Hint: Using the law of reflection, it is known that the ray will reflect at ${90}^{\circ }$. So, the ray shall trace back the same path after reflecting from the mirror.

Complete step-by-step solution -

Refraction is a phenomenon that occurs when light changes its travelling medium. Different mediums have different optical densities. A denser medium has more optical density than a rarer medium.
It is observed that, when light goes from a rarer medium to a denser medium it bends towards the normal. When light goes from a denser medium to a rarer medium, it bends away from the normal.
The relation between the angles made as light changes its medium and the relative refractive index is given by the Snell’s law:
$$\mu ={\displaystyle \frac{\sin (i)}{\sin (r)}}$$
The principle of reversibility states that light retraces the same path if the direction of travel of light is reversed. There are no changes, losses or further bending if the path of light is just reversed, which can be achieved by placing a mirror in the path of the light just perpendicular to its passage. It can be concluded that reversibility principle is a simple deduction of Snell’s law.
So, here in the question, as the light strikes the mirror at perpendicular angles it retraces the exact path. So, the principle of reversibility has been used.

Note: From Snell’s law, it’s known that refracted and incident angles occur in pairs. So at the interface of the mediums, the incident angle in the return journey was the refracted angle before reflection. So, the ray traced back the same path after refraction too.