A student wishes to study the cell structure under a light microscope having 10 x eyepiece and 45 x objective. He should Illuminate the object, by which one of the following colours of light, the best possible resolution can be achieved?
A. Yellow
B. Green
C. Blue
D. Red
Answer
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Hint: Resolution of the microscope is inversely balanced to the wavelength of the glow utilized. Blue light is considered to have a minimum wavelength as well as maximum resolution.
Step by step answer:Resolving power is the proficiency to determine two close items as distinct. It is computed by the formula of 0.61 $\lambda $/ numerical aperture, where $\lambda $ stands for the wavelength of light as well as the numerical opening is the light obtaining capacity of the lens. The visible spectrum is the quantity of the electromagnetic spectrum that is visible to the human eye. Electromagnetic radiation in this distance of wavelengths is known as visible light or as simply light.
Certainly, after calculations, the value comes out to be 0.5 $\lambda $ or one half the wavelength of brightening light. The regular wavelength of light utilized in microscopes is 500-600 nm. It provides an ultimate determination of 250-300 nm or 0.25 micrometers to 0.3 micrometers for the optical microscope.
Option – A – Yellow: Is not the right option as the blue light is used for the best possible resolution.
Option – B – Green: This is not an appropriate answer to the question as the green light is not used for the best possible Resolution.
Option – C – Blue: This option is the valid answer as Blue light is used for the best possible resolution.
Option – D – Red: Is not the right option to this answer as blue light is used for the best possible resolution.
Thus, correct answer is option – C “Blue”
Note: Use of blue light also referred to as blue filters abet in attaining a finding limit of 200 nm or 0.2 micrometers. This due to blue light has a lower wavelength as correlated to red, yellow as well as the green light.
Step by step answer:Resolving power is the proficiency to determine two close items as distinct. It is computed by the formula of 0.61 $\lambda $/ numerical aperture, where $\lambda $ stands for the wavelength of light as well as the numerical opening is the light obtaining capacity of the lens. The visible spectrum is the quantity of the electromagnetic spectrum that is visible to the human eye. Electromagnetic radiation in this distance of wavelengths is known as visible light or as simply light.
Certainly, after calculations, the value comes out to be 0.5 $\lambda $ or one half the wavelength of brightening light. The regular wavelength of light utilized in microscopes is 500-600 nm. It provides an ultimate determination of 250-300 nm or 0.25 micrometers to 0.3 micrometers for the optical microscope.
Option – A – Yellow: Is not the right option as the blue light is used for the best possible resolution.
Option – B – Green: This is not an appropriate answer to the question as the green light is not used for the best possible Resolution.
Option – C – Blue: This option is the valid answer as Blue light is used for the best possible resolution.
Option – D – Red: Is not the right option to this answer as blue light is used for the best possible resolution.
Thus, correct answer is option – C “Blue”
Note: Use of blue light also referred to as blue filters abet in attaining a finding limit of 200 nm or 0.2 micrometers. This due to blue light has a lower wavelength as correlated to red, yellow as well as the green light.
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