Question

A temperature difference of \[{27^ \circ }C\] on the Kelvin scale is:
A) $27K$
B) $300K$
C) $ - 246K$
D) Zero

Answer 1

Hint:It is to be noted that Kelvin and Celsius are just the different ways to measure the temperature. This means that their names can be different but their function is the same. Also they are convertible from one scale to another.

Step-by-Step Explanation:
Step I:
As it is known that both the scales are related. The difference between the boiling and freezing point of water is the same in Kelvin as well as Celsius scale. Both of them have a difference of a hundred divisions in their boiling and melting points . Therefore the magnitude of the Kelvin scale will also be equal to that of the Celsius scale.
$\Delta {T_{Kelvin}} = \Delta {T_{Celsius}}$
Step II:
It is given that
$\Delta {T_{Celsius}} = {27^ \circ }C$
Relation between Kelvin and Celsius scale can be written as
$\Delta {T_{Kelvin}} = \Delta {T_{Celsius}} + 273$
Step III:
Since it is clear that the temperature difference of Kelvin and Celsius scale is equal, therefore the temperature difference on Kelvin scale will also be $27K$.

Hence option A is the right answer.

Note:
The branch of physics in which one form of energy is converted to some other form of energy is known as thermodynamics. It can vary according to the temperature of the body. If the bodies are at the same temperature this means that there is no heat flow or exchange between the bodies. Otherwise if they are at different temperatures then the heat transfers from hotter body to the colder body. Temperature describes the hotness or coldness of a body. The amount of internal energy in two bodies is measured by temperature difference.