Answer
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Hint: Due to the delocalization of pi electrons in benzene there is a possibility of resonance. As a result of these the bonds keep switching fast so that the bond can be thought of as an average between the $C-C$ single and double bonds.
Complete step by step answer:
- As we know benzene (${{C}_{6}}{{H}_{6}}$) is an aromatic hydrocarbon which have a cyclic structure with six carbon atoms and six hydrogen atoms. In the benzene molecule, each of the carbon atoms is attached with two other carbon atoms and one hydrogen atom.
- Since benzene has more than one way to place double bonds in the ring, it exhibits resonance and has two resonating structures. During resonance the arrangement of electrons differs and double bonds delocalize and give stability to benzene. The resonance structures of benzene are given below,
- In benzene each of the carbon atom is $s{{p}^{2}}$ hybridized and due to resonance or the delocalization of $\pi $electron clouds below and above the plane of benzene ring ,all C,C bonds have slightly double bond character. As a result, the carbon-carbon bond length in benzene lies between the $C-C$ single bond length and $C-C$ double bond length.
- It is observed that the $C-C$ bond length in benzene is 139 pm which lies between the standard $C-C$ single bond length (154 pm) and $C-C$ double bond length (134 pm).
- Hence both (A) and (R) are correct and as we have seen (R) is the correct explanation of (A).
Therefore, the answer is option (A).
Note: It should be noted that among the resonance structures of benzene given, the first two are the resonating structure and the third one is the hybrid structure. This hybrid structure is more stable than the other two resonating structures as the hybrid structure has the low energy. These resonance structures are also called Kekule structures.
Complete step by step answer:
- As we know benzene (${{C}_{6}}{{H}_{6}}$) is an aromatic hydrocarbon which have a cyclic structure with six carbon atoms and six hydrogen atoms. In the benzene molecule, each of the carbon atoms is attached with two other carbon atoms and one hydrogen atom.
- Since benzene has more than one way to place double bonds in the ring, it exhibits resonance and has two resonating structures. During resonance the arrangement of electrons differs and double bonds delocalize and give stability to benzene. The resonance structures of benzene are given below,
- In benzene each of the carbon atom is $s{{p}^{2}}$ hybridized and due to resonance or the delocalization of $\pi $electron clouds below and above the plane of benzene ring ,all C,C bonds have slightly double bond character. As a result, the carbon-carbon bond length in benzene lies between the $C-C$ single bond length and $C-C$ double bond length.
- It is observed that the $C-C$ bond length in benzene is 139 pm which lies between the standard $C-C$ single bond length (154 pm) and $C-C$ double bond length (134 pm).
- Hence both (A) and (R) are correct and as we have seen (R) is the correct explanation of (A).
Therefore, the answer is option (A).
Note: It should be noted that among the resonance structures of benzene given, the first two are the resonating structure and the third one is the hybrid structure. This hybrid structure is more stable than the other two resonating structures as the hybrid structure has the low energy. These resonance structures are also called Kekule structures.
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