Answer
402.3k+ views
Hint: You could firstly represent the given situation in a neat diagram. Now take the displacement of the plank as x then, the displacement of the man will be 10-x. Then, you could recall the expression for net displacement of the system, and then substituting accordingly will give you the required displacement.
Formula used:
The net displacement of the system,
$S=\dfrac{{{m}_{1}}{{r}_{1}}+{{m}_{2}}{{r}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
Complete step-by-step solution
In the question, we are given a 20kg wooden plank that lies on a smooth floor. A 60kg man walks across this plank of 10m. We are asked to find the displacement of the plank over the floor as the man reaches the other end of the plank. So the situation is as represented below,
As the floor is smooth, there will be no friction, also, there is no mention of any external force, so, the net displacement of the center of mass should be zero.
We know that the net displacement of the center of mass of the system is given by,
$S=\dfrac{{{m}_{1}}{{r}_{1}}+{{m}_{2}}{{r}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
Here, ${{m}_{1}}$ is the mass of the plank, ${{m}_{2}}$ is the mass of the man, ${{r}_{1}}$ is the displacement of the scale and ${{r}_{2}}$ is the displacement of the man.
Substituting according gives,
$S=\dfrac{20\times \left( -x \right)+60\times \left( 10-x \right)}{20+60}$
But, net displacement of the centre of mass of the system is zero here, so,
$\dfrac{20\times \left( -x \right)+60\times \left( 10-x \right)}{20+60}=0$
$\Rightarrow -20x+600-60x=0$
$\Rightarrow 80x=600$
$\therefore x=\dfrac{600}{80}=7.5m$
Therefore, the displacement of the plank over the floor when the man reaches the other end of the plank is found to be 7.5m.
Note: If you are wondering why we have taken negative signs for the displacement of the plank, it is to symbolize the displacement of the plank opposite to the displacement of man. Relating the situation to some real-life experience you will realize that this is exactly what happens in such a situation. Hence the negative sign.
Formula used:
The net displacement of the system,
$S=\dfrac{{{m}_{1}}{{r}_{1}}+{{m}_{2}}{{r}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
Complete step-by-step solution
In the question, we are given a 20kg wooden plank that lies on a smooth floor. A 60kg man walks across this plank of 10m. We are asked to find the displacement of the plank over the floor as the man reaches the other end of the plank. So the situation is as represented below,
![seo images](https://www.vedantu.com/question-sets/59467713-7fb8-4fa7-9a6e-fd17ed9fec672762055676474927650.png)
As the floor is smooth, there will be no friction, also, there is no mention of any external force, so, the net displacement of the center of mass should be zero.
We know that the net displacement of the center of mass of the system is given by,
$S=\dfrac{{{m}_{1}}{{r}_{1}}+{{m}_{2}}{{r}_{2}}}{{{m}_{1}}+{{m}_{2}}}$
Here, ${{m}_{1}}$ is the mass of the plank, ${{m}_{2}}$ is the mass of the man, ${{r}_{1}}$ is the displacement of the scale and ${{r}_{2}}$ is the displacement of the man.
Substituting according gives,
$S=\dfrac{20\times \left( -x \right)+60\times \left( 10-x \right)}{20+60}$
But, net displacement of the centre of mass of the system is zero here, so,
$\dfrac{20\times \left( -x \right)+60\times \left( 10-x \right)}{20+60}=0$
$\Rightarrow -20x+600-60x=0$
$\Rightarrow 80x=600$
$\therefore x=\dfrac{600}{80}=7.5m$
Therefore, the displacement of the plank over the floor when the man reaches the other end of the plank is found to be 7.5m.
Note: If you are wondering why we have taken negative signs for the displacement of the plank, it is to symbolize the displacement of the plank opposite to the displacement of man. Relating the situation to some real-life experience you will realize that this is exactly what happens in such a situation. Hence the negative sign.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Guru Purnima speech in English in 100 words class 7 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Select the word that is correctly spelled a Twelveth class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)