Answer
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Hint: This question is based on the concept of refraction of light and laws of refraction when a ray of light goes from the optically rarer medium to optically denser medium, the refracted ray bends towards the normal and snell’s laws of refraction
Complete step by step solution:
According to the question, Refraction of light at the boundary between two different region based on two law of refraction which is
-The ratio of the sine of angle of incident to the sine of angle of refraction is constant called Snell’s law of refraction.
$\mu = \dfrac{{\operatorname{sin} i}}{{\operatorname{sin} r}}$
-The incident ray, the refracted ray and normal to the interface surface at the point of incidence, which means all lie in the same plane
Hence, the correct option is C (Both A and B)
Note:Laws of refraction have the same frequency (Colour) of refracted ray remain unchanged and the intensity of the refracted ray is less than that of incident ray. Moreover if a ray of light passes normally then it does not bend or deviate from its path.
Complete step by step solution:
According to the question, Refraction of light at the boundary between two different region based on two law of refraction which is
-The ratio of the sine of angle of incident to the sine of angle of refraction is constant called Snell’s law of refraction.
$\mu = \dfrac{{\operatorname{sin} i}}{{\operatorname{sin} r}}$
-The incident ray, the refracted ray and normal to the interface surface at the point of incidence, which means all lie in the same plane
Hence, the correct option is C (Both A and B)
Note:Laws of refraction have the same frequency (Colour) of refracted ray remain unchanged and the intensity of the refracted ray is less than that of incident ray. Moreover if a ray of light passes normally then it does not bend or deviate from its path.
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