
Air contains nitrogen and oxygen in the volume ratio of 4:1 .The average vapour density of air is :
A.30
B.28.8
C.28
D.14.4
Answer
557.4k+ views
Hint:Nitrogen and oxygen are present by volume , so first we will calculate the total molecular mass of air. We will then keep this valve of molecular mass in the vapour density formula and calculate the value of vapour density.
Complete step by step answer:
Nitrogen and oxygen are present in the volume ratio of 4:1 . It means 80% nitrogen and 20% oxygen are present in the gas.
Vapour Density of a gas is the relative ratio of the density of that gas to that of density of hydrogen gas. Mathematically,
Vapour density =$\dfrac{{density(gas)}}{{density({H_2})}}$.
We will use this equation to procced through the question. We will now learn to calculate density of a gas.
From ideal gas equation we have,
$
PV = nRT \\
PV = \dfrac{w}{M}RT \\
\dfrac{{PM}}{{RT}} = \dfrac{w}{V} \\
$
Where
$
P = pressure \\
V = volume \\
T = temperature \\
n = moles \\
$
Since ,
$\dfrac{w}{V} = density(gas)$
We can rewrite the above equation as ${d_{gas}} = \dfrac{{PM}}{{RT}}$……….(i) . This is the general equation of calculating the density of any gas. Keeping all other factors constant , density depends on molecular mass of gas i.e. $M$.
We can now write it as :
Vapour density = $\dfrac{{{d_{gas}}}}{{{d_{{H_2}}}}} = \dfrac{{{M_{gas}}}}{{{M_{{H_2}}}}}$.
Since the molecular mass of hydrogen gas is 2. The equation gets reduced to-
$VD = \dfrac{{{M_{gas}}}}{2}$…………(ii)
We will now calculate the molecular mass of the gas.
${M_{gas}} = \dfrac{{80}}{{100}} \times m({N_2}) + \dfrac{{20}}{{100}} \times m({O_2})$
$
{M_{gas}} = \dfrac{4}{5} \times 28 + \dfrac{1}{5} \times 32 \\
{M_{gas}} = 22.4 + 6.4 \\
{M_{gas}} = 28.8 \\
\\
$
We know the relation between density and molecular mass . Now using that:
From equation (ii),
$
VD = \dfrac{{{M_{gas}}}}{2} \\
VD = \dfrac{{28.8}}{2} \\
VD = 14.4 \\
$
Hence, option (D) is correct.
Note: Vapour density is a unitless quantity . Vapour density is only calculated for gas and vapour. There are only 14 gases and vapour with a vapour density less than one, i.e. they are lighter than air. The density and vapour density of a gas are not the same. More the vapour density of a gas, the heavier the gas will be.
Complete step by step answer:
Nitrogen and oxygen are present in the volume ratio of 4:1 . It means 80% nitrogen and 20% oxygen are present in the gas.
Vapour Density of a gas is the relative ratio of the density of that gas to that of density of hydrogen gas. Mathematically,
Vapour density =$\dfrac{{density(gas)}}{{density({H_2})}}$.
We will use this equation to procced through the question. We will now learn to calculate density of a gas.
From ideal gas equation we have,
$
PV = nRT \\
PV = \dfrac{w}{M}RT \\
\dfrac{{PM}}{{RT}} = \dfrac{w}{V} \\
$
Where
$
P = pressure \\
V = volume \\
T = temperature \\
n = moles \\
$
Since ,
$\dfrac{w}{V} = density(gas)$
We can rewrite the above equation as ${d_{gas}} = \dfrac{{PM}}{{RT}}$……….(i) . This is the general equation of calculating the density of any gas. Keeping all other factors constant , density depends on molecular mass of gas i.e. $M$.
We can now write it as :
Vapour density = $\dfrac{{{d_{gas}}}}{{{d_{{H_2}}}}} = \dfrac{{{M_{gas}}}}{{{M_{{H_2}}}}}$.
Since the molecular mass of hydrogen gas is 2. The equation gets reduced to-
$VD = \dfrac{{{M_{gas}}}}{2}$…………(ii)
We will now calculate the molecular mass of the gas.
${M_{gas}} = \dfrac{{80}}{{100}} \times m({N_2}) + \dfrac{{20}}{{100}} \times m({O_2})$
$
{M_{gas}} = \dfrac{4}{5} \times 28 + \dfrac{1}{5} \times 32 \\
{M_{gas}} = 22.4 + 6.4 \\
{M_{gas}} = 28.8 \\
\\
$
We know the relation between density and molecular mass . Now using that:
From equation (ii),
$
VD = \dfrac{{{M_{gas}}}}{2} \\
VD = \dfrac{{28.8}}{2} \\
VD = 14.4 \\
$
Hence, option (D) is correct.
Note: Vapour density is a unitless quantity . Vapour density is only calculated for gas and vapour. There are only 14 gases and vapour with a vapour density less than one, i.e. they are lighter than air. The density and vapour density of a gas are not the same. More the vapour density of a gas, the heavier the gas will be.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

