Answer
Verified
463.5k+ views
Hint: Angular velocity of the motor is the rate of rotation of the conductors associated in the motor with respect to time. It is denoted by $\omega $ and is abbreviated as omega. It is measured in radians per seconds. The frequency is the rate at which the conductor occupies the pre-defined space in the motor. It is denoted by f and is measured in Hertz.
Here in the question, we need to determine the frequency of rotation of the motor such that the angular velocity of the electric motor is given as 125 radians per seconds. For this, we will use the general relation between the angular speed and the frequency as $\omega = 2\pi f$.
Complete step by step answer:
The angular velocity of the conductor in an electric motor is the product of the frequency of the rotation of the motor and the total circular radian. Mathematically, $\omega = 2\pi f$ where, $\omega $ is in radian per seconds and $f$ is in Hertz.
Here, $\omega = 125{\text{ rad/sec}}$ so, substituting the same in the formula $\omega = 2\pi f$ to determine the frequency of rotation.
$
\omega = 2\pi f \\
125 = 2\pi f \\
f = \dfrac{{125 \times 7}}{{2 \times 22}} \\
= \dfrac{{875}}{{44}} \\
= 19.88{\text{ Hz}} \\
\approx {\text{20 Hz}} \\
$
Hence, the frequency of rotation of an electric motor of 12 horsepower generates an angular velocity of 125 radians per second is 20 Hz.
Option A is correct.
Note: It is interesting to note here that the power rating of the electric motor has been given in the question is of no use. It is just added as an added information
Here in the question, we need to determine the frequency of rotation of the motor such that the angular velocity of the electric motor is given as 125 radians per seconds. For this, we will use the general relation between the angular speed and the frequency as $\omega = 2\pi f$.
Complete step by step answer:
The angular velocity of the conductor in an electric motor is the product of the frequency of the rotation of the motor and the total circular radian. Mathematically, $\omega = 2\pi f$ where, $\omega $ is in radian per seconds and $f$ is in Hertz.
Here, $\omega = 125{\text{ rad/sec}}$ so, substituting the same in the formula $\omega = 2\pi f$ to determine the frequency of rotation.
$
\omega = 2\pi f \\
125 = 2\pi f \\
f = \dfrac{{125 \times 7}}{{2 \times 22}} \\
= \dfrac{{875}}{{44}} \\
= 19.88{\text{ Hz}} \\
\approx {\text{20 Hz}} \\
$
Hence, the frequency of rotation of an electric motor of 12 horsepower generates an angular velocity of 125 radians per second is 20 Hz.
Option A is correct.
Note: It is interesting to note here that the power rating of the electric motor has been given in the question is of no use. It is just added as an added information
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE