Question

Arrange the following resonating structures according to decreasing order of stability

1. \[\;1{\text{ }} > {\text{ }}2{\text{ }} > {\text{ }}3\]
2. \[\;2{\text{ }} > {\text{ }}1{\text{ }} > {\text{ }}3\]
3. \[\;3{\text{ }} > {\text{ }}1{\text{ }} > {\text{ }}2\]
4. \[3{\text{ }} > {\text{ }}2{\text{ }} > {\text{ }}1\]

Answer 1

Hint: In the given question the stability of the resonating structures has been asked. Though the stability of acrolein. Acrolein is a colorless or yellow liquid with a specific odor and is used as a pesticide to control mollusks, weeds, bacteria, and algae.

Complete Step by step answer: We know that the stability of resonance increases with the increase in Number of covalent bonds, also the Number of atoms within an octet of electrons as exception in hydrogen because it has a duplex, also in the Separation of opposite charges followed with Dispersal of charge. So that a negative charge if any on a more electronegative atom, a positive charge if any on the more electropositive atom, increases the stability of the atom. Stability of the resonating structures depends on the following points they are as follows-First is that the equivalent resonating structure will Subsidize equally toward the right-hand side, but if resonating structures are not equivalent, they do so in course of their stability.
From the above structure we can say that the most stable structure is 1 then 2 and then 3.

Hence, option 1 is correct.

Note: The order of Stability of the resonating structure will be like that, electronegative element having incomplete octet and positive charge that the non-polar compounds will be on the right hand side. Non-polar resonating structure, Polar with Complete octet of their atoms has maximum no of Covalent bonds. If negative charge is present it should be a more electronegative element. Less charge separation is more stable than more charge separation.