Answer
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Hint In these kinds of situations the first thing important is to notice the given problem statement. We can observe that this is a question for the straight approach. In this question we just have to put the question for the interconversion and put the values to get the answer.
Complete step by step answer:
The values in celsius and fahrenheit scale is interconverted by the equation:
$F = \dfrac{9}{5}C + 32$
Now we just have to consider the values be $F = 2x{\text{ and }}C = x$
Therefore, just put the values:
$
2x = \dfrac{9}{5}x + 32 \\
\Rightarrow 2x - \dfrac{9}{5}x = 32 \\
\Rightarrow \dfrac{1}{5}x = 32 \\
\Rightarrow x = 32\times 5 \\
\Rightarrow x = {160^o} \\
$
Note Most important thing here is to notice the given values, then we can easily interpret the equations. We just have to take care of assuming the values correctly as this is the most common mistake that happens.
Complete step by step answer:
The values in celsius and fahrenheit scale is interconverted by the equation:
$F = \dfrac{9}{5}C + 32$
Now we just have to consider the values be $F = 2x{\text{ and }}C = x$
Therefore, just put the values:
$
2x = \dfrac{9}{5}x + 32 \\
\Rightarrow 2x - \dfrac{9}{5}x = 32 \\
\Rightarrow \dfrac{1}{5}x = 32 \\
\Rightarrow x = 32\times 5 \\
\Rightarrow x = {160^o} \\
$
Note Most important thing here is to notice the given values, then we can easily interpret the equations. We just have to take care of assuming the values correctly as this is the most common mistake that happens.
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