Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

How many atoms of neon are in 5.9 grams of neon?

Answer
VerifiedVerified
459k+ views
like imagedislike image
Hint: Avogadro's Number speaks to the complete number of particles or atoms present in one mole of any substance. It is a steady worth and is utilized in computing the quantity of rudimentary particles present in a given example of any substance. The estimation of Avogadro's Number is 6.023×1023 particles or atoms per mole.

Complete step by step answer:
The thought here is that you need to utilize neon's molar mass, which mentions to you what the mass of one mole of the component is, to decide the number of moles you have in that 5.9g test.
When you know the number of moles you have, you can utilize Avogadro's number to locate the quantity of molecules.
Thus, neon has a molar mass of 20.18 g/mol , which implies that each mole of neon has a mass of 20.18 g .
Your example of neon will along these lines contain
5.9g1 mole Ne20.18g=0.2924 moles Ne
Presently, you realize that one mole of any component contains precisely 6.0221023 particles of that component - this is Avogadro's number.
All things considered, on the off chance that one mole contains that numerous particles, it follows that you test will contain
0.2924moles Ne6.0221023atoms of Ne1mole Ne=[1.81023atoms] of Ne
The appropriate response is adjusted to two sig figs, the quantity of sig figs you have for the mass of the example

Note: Molality and molarity are two unique ideas. Molality is fundamentally the proportion of the quantity of moles of the substance to the absolute volume of the arrangement. Then again, molality is spoken to as the proportion of the quantity of moles of the substance to the complete mass of the dissolvable. Both these amounts are incredibly valuable while addressing questions identified with substance focuses.