Answer
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Hint: A compound that can react as an acid as well as a base is said to be amphoteric in nature.
Complete step by step answer: Consider the reaction,
${\text{BeO + 2NaOH }} \to {\text{ N}}{{\text{a}}_2}{\text{Be}}{{\text{O}}_2}{\text{ + }}{{\text{H}}_2}{\text{O}}$
In this reaction, ${\text{BeO}}$ reacts with a sodium hydroxide base $\left( {{\text{NaOH}}} \right)$ to produce a salt sodium beryllate $\left( {{\text{N}}{{\text{a}}_2}{\text{Be}}{{\text{O}}_2}} \right)$ and water.
In this reaction, ${\text{BeO}}$ acts as an acid. It reacts with a base to give salt and water.
${\text{BeO + 2HCl }} \to {\text{ BeC}}{{\text{l}}_2}{\text{ + }}{{\text{H}}_2}{\text{O}}$
In this reaction, ${\text{BeO}}$ reacts with hydrochloric acid $\left( {{\text{HCl}}} \right)$ to produce a salt barium chloride $\left( {{\text{BeC}}{{\text{l}}_2}} \right)$ and water.
In this reaction, ${\text{BeO}}$ acts as a base. It reacts with an acid to give salt and water.
Thus, ${\text{BeO}}$ reacts as an acid and as well as a base. Thus, ${\text{BeO}}$ is amphoteric.
Thus, the statement is true.
Additional Information: Other examples of amphoteric compounds are:
-Water $\left( {{{\text{H}}_2}{\text{O}}} \right)$
-Aluminum oxide $\left( {{\text{A}}{{\text{l}}_2}{{\text{O}}_3}} \right)$
-Lead oxides $\left( {{\text{PbO, Pb}}{{\text{O}}_2}} \right)$
-Beryllium hydroxide $\left( {{\text{Be(OH}}{{\text{)}}_2}} \right)$
-Tin oxide $\left( {{\text{SnO}}} \right)$
-Zinc hydroxide $\left( {{\text{Zn(OH}}{{\text{)}}_2}} \right)$
-Tin hydroxide $\left( {{\text{Sn(OH}}{{\text{)}}_2}} \right)$
-Lead hydroxide $\left( {{\text{Pb(OH}}{{\text{)}}_2}} \right)$
Note: The reaction in which an acid reacts with a base to produce salt and water is known as a neutralization reaction.
The given reactions are neutralization reactions. In the first reaction, ${\text{BeO}}$ reacts with a sodium hydroxide base to produce sodium beryllate which is a salt and water. Here, ${\text{BeO}}$ acts as an acid. In the second reaction, ${\text{BeO}}$ reacts with hydrochloric acid to produce barium chloride which is a salt and water. Here, ${\text{BeO}}$ acts as a base.
Thus, ${\text{BeO}}$ is amphoteric in nature.
Complete step by step answer: Consider the reaction,
${\text{BeO + 2NaOH }} \to {\text{ N}}{{\text{a}}_2}{\text{Be}}{{\text{O}}_2}{\text{ + }}{{\text{H}}_2}{\text{O}}$
In this reaction, ${\text{BeO}}$ reacts with a sodium hydroxide base $\left( {{\text{NaOH}}} \right)$ to produce a salt sodium beryllate $\left( {{\text{N}}{{\text{a}}_2}{\text{Be}}{{\text{O}}_2}} \right)$ and water.
In this reaction, ${\text{BeO}}$ acts as an acid. It reacts with a base to give salt and water.
${\text{BeO + 2HCl }} \to {\text{ BeC}}{{\text{l}}_2}{\text{ + }}{{\text{H}}_2}{\text{O}}$
In this reaction, ${\text{BeO}}$ reacts with hydrochloric acid $\left( {{\text{HCl}}} \right)$ to produce a salt barium chloride $\left( {{\text{BeC}}{{\text{l}}_2}} \right)$ and water.
In this reaction, ${\text{BeO}}$ acts as a base. It reacts with an acid to give salt and water.
Thus, ${\text{BeO}}$ reacts as an acid and as well as a base. Thus, ${\text{BeO}}$ is amphoteric.
Thus, the statement is true.
Additional Information: Other examples of amphoteric compounds are:
-Water $\left( {{{\text{H}}_2}{\text{O}}} \right)$
-Aluminum oxide $\left( {{\text{A}}{{\text{l}}_2}{{\text{O}}_3}} \right)$
-Lead oxides $\left( {{\text{PbO, Pb}}{{\text{O}}_2}} \right)$
-Beryllium hydroxide $\left( {{\text{Be(OH}}{{\text{)}}_2}} \right)$
-Tin oxide $\left( {{\text{SnO}}} \right)$
-Zinc hydroxide $\left( {{\text{Zn(OH}}{{\text{)}}_2}} \right)$
-Tin hydroxide $\left( {{\text{Sn(OH}}{{\text{)}}_2}} \right)$
-Lead hydroxide $\left( {{\text{Pb(OH}}{{\text{)}}_2}} \right)$
Note: The reaction in which an acid reacts with a base to produce salt and water is known as a neutralization reaction.
The given reactions are neutralization reactions. In the first reaction, ${\text{BeO}}$ reacts with a sodium hydroxide base to produce sodium beryllate which is a salt and water. Here, ${\text{BeO}}$ acts as an acid. In the second reaction, ${\text{BeO}}$ reacts with hydrochloric acid to produce barium chloride which is a salt and water. Here, ${\text{BeO}}$ acts as a base.
Thus, ${\text{BeO}}$ is amphoteric in nature.
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