Answer
Verified
445.5k+ views
Hint: As per the question asked, we have to find out the bond angle of the water molecule which can be derived by knowing that the oxygen in the water molecule has four electron groups (i.e. two lone pairs of electrons). So, the molecule will have two lone pairs and two bond pairs giving it a tetrahedral electron geometry.
Complete step by step answer:
We should know that,
Water i.e. ${{H}_{2}}O$, is a polar molecule with one oxygen atom bonded to the two different hydrogen atoms. Due to high electronegativity of oxygen atoms, the bond formed (i.e. covalent bond) between oxygen and hydrogen is polar.
Hence, oxygen atom acquires two partial negative charges whereas, each hydrogen atom acquires one partial positive charge.
So, oxygen has two lone pairs of electrons. Thus, now water molecules have two bond pairs and two lone pairs of electrons which are arranged in tetrahedral geometry around the central atom which is oxygen.
Normally, we know that tetrahedral bond angle is ${{109.5}^{o}}$, but in water molecule, because of the presence of two lone pair-lone pair repulsion and lone pair-bond pair repulsion, the bond angle gets decreased from ${{109.5}^{o}}$ to ${{104.5}^{o}}$ which is approximately ${{105}^{o}}$.
Leaving the lone pairs, the shape of the water molecule will be bent shaped.
We know that, oxygen atom acquires $s{{p}^{3}}$ hybridisation. Because of the polarity of the bonds, water molecules have high dipole moments where negative charge is directed towards the lone pair.
As we know that, polar molecules attract each other by dipole-dipole forces where the negative part of one water molecule is attracted to the positive part of another water molecule. So here, in water molecules the hydrogen atom has low density. Thus, the hydrogen atom of one molecule is attracted to the lone pair of the oxygen atom of another molecule. Thereby decreasing its bond angle.
So, the correct answer is “Option C”.
Note: We should know that, the lone pair-lone pair repulsions are of the greatest magnitude and bond pair-bond pair repulsions are of the lowest magnitude and the lone pair-bond pair repulsions are greater than bond pair-bond pair and lower than the lone pair-lone pair repulsions.
Complete step by step answer:
We should know that,
Water i.e. ${{H}_{2}}O$, is a polar molecule with one oxygen atom bonded to the two different hydrogen atoms. Due to high electronegativity of oxygen atoms, the bond formed (i.e. covalent bond) between oxygen and hydrogen is polar.
Hence, oxygen atom acquires two partial negative charges whereas, each hydrogen atom acquires one partial positive charge.
So, oxygen has two lone pairs of electrons. Thus, now water molecules have two bond pairs and two lone pairs of electrons which are arranged in tetrahedral geometry around the central atom which is oxygen.
Normally, we know that tetrahedral bond angle is ${{109.5}^{o}}$, but in water molecule, because of the presence of two lone pair-lone pair repulsion and lone pair-bond pair repulsion, the bond angle gets decreased from ${{109.5}^{o}}$ to ${{104.5}^{o}}$ which is approximately ${{105}^{o}}$.
Leaving the lone pairs, the shape of the water molecule will be bent shaped.
We know that, oxygen atom acquires $s{{p}^{3}}$ hybridisation. Because of the polarity of the bonds, water molecules have high dipole moments where negative charge is directed towards the lone pair.
As we know that, polar molecules attract each other by dipole-dipole forces where the negative part of one water molecule is attracted to the positive part of another water molecule. So here, in water molecules the hydrogen atom has low density. Thus, the hydrogen atom of one molecule is attracted to the lone pair of the oxygen atom of another molecule. Thereby decreasing its bond angle.
So, the correct answer is “Option C”.
Note: We should know that, the lone pair-lone pair repulsions are of the greatest magnitude and bond pair-bond pair repulsions are of the lowest magnitude and the lone pair-bond pair repulsions are greater than bond pair-bond pair and lower than the lone pair-lone pair repulsions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Change the following sentences into negative and interrogative class 10 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE