Answer
Verified
457.5k+ views
Hint: To find no. of atoms firstly find the number of moles of each element.No. of moles is equal to the ratio of given mass and molar mass. No. of molecules of a substance is equal to the product of no. of moles of given substance and Avogadro number.
Step by step answer:1st Case is of 12g of carbon,
Given mass of carbon= 12g
Molar mass of carbon = 12g/mole
And we know that, No. of moles of atom= given mass/molar mass
And by putting values we get, no. of moles of carbon =12/12 = 1 mole
And no. of molecules= no. of moles $ \times $ Avogadro no.
Therefore by putting values,
No. of molecules of carbon= 1 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of carbon = 6.022$ \times $${10^{23}}$ molecules
2nd Case is of 64g of oxygen,
Given mass of oxygen = 64g
Molar mass of oxygen = 16g/mole
And by putting values we get, no. of moles of oxygen =64/16 = 4 moles
Now by putting values,
No. of molecules of oxygen = 4 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of oxygen = 24.088$ \times $${10^{23}}$ molecules
3rd Case is of 72g of water,
Given mass of water = 72g
Molar mass of water = 2$ \times $1 + 16
Molar mass of water =18g/mole
And by putting values we get, no. of moles of water=72/18 = 4 moles
Now by putting values,
No. of molecules of water = 4 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of water = 24.088$ \times $${10^{23}}$ molecules
Note: Avogadro's number is the number of units in one mole of any substance (defined as its molecular weight in grams), its value is equal to 6.02214076 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.
Step by step answer:1st Case is of 12g of carbon,
Given mass of carbon= 12g
Molar mass of carbon = 12g/mole
And we know that, No. of moles of atom= given mass/molar mass
And by putting values we get, no. of moles of carbon =12/12 = 1 mole
And no. of molecules= no. of moles $ \times $ Avogadro no.
Therefore by putting values,
No. of molecules of carbon= 1 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of carbon = 6.022$ \times $${10^{23}}$ molecules
2nd Case is of 64g of oxygen,
Given mass of oxygen = 64g
Molar mass of oxygen = 16g/mole
And by putting values we get, no. of moles of oxygen =64/16 = 4 moles
Now by putting values,
No. of molecules of oxygen = 4 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of oxygen = 24.088$ \times $${10^{23}}$ molecules
3rd Case is of 72g of water,
Given mass of water = 72g
Molar mass of water = 2$ \times $1 + 16
Molar mass of water =18g/mole
And by putting values we get, no. of moles of water=72/18 = 4 moles
Now by putting values,
No. of molecules of water = 4 $ \times $ 6.022 $ \times $${10^{23}}$
No. of molecules of water = 24.088$ \times $${10^{23}}$ molecules
Note: Avogadro's number is the number of units in one mole of any substance (defined as its molecular weight in grams), its value is equal to 6.02214076 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
When was Karauli Praja Mandal established 11934 21936 class 10 social science CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Why is steel more elastic than rubber class 11 physics CBSE
Distinguish between the following Ferrous and nonferrous class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE