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How do you calculate the sample range, sample mean, sample median, sample variance and sample standard deviation of 18,19,34,38,24,18,22,51,44,14,29?

Answer
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Hint: We first express the given sample inputs in ascending order. Then we express the individual process and formulas to find sample range, sample mean, sample median, sample variance and sample standard deviation.

Complete step by step solution:
We have been given a sample of 11 discrete data 18,19,34,38,24,18,22,51,44,14,29 and we need to find their sample range, sample mean, sample median, sample variance and sample standard deviation. In this sample n=11.
Arranging them in ascending order we get 14,18,18,19,22,24,29,34,38,44,51. We consider the inputs as xi,i=1(1)11.
We express the mathematical formulas to find those attributes and put the values.
Sample range is equal to the difference between the highest and lowest value of the whole sample which is 5114=37.
Sample mean can be expressed as x=xin. Putting the values, we get
x=14+18+18+19+22+24+29+34+38+44+5111=31111=28.28.
Sample median is expressed as the middle point of the ordered sample either in ascending or descending order. In this case of 14,18,18,19,22,24,29,34,38,44,51, the median is 24.
Sample variance can be expressed as σ2=1nxi2(x)2. Now we find
xi2=142+182+182+192+222+242+292+342+382+442+512xi2=10243
Putting the values, we get σ2=111(10243)(28.28)2=15952121=131.83.
Sample standard deviation can be expressed as σ=σ2=1nxi2(x)2. Putting the values, we get σ=131.83=11.48.

Note:
These all-required attributes are the measurement of central tendency and dispersion. The sample range, sample mean, sample median is part of central tendency and sample variance and sample standard deviation are part of dispersion.