
Change the following from exponential form to logarithmic form.
1) \[{3^4} = 81\]
2) \[{6^{ - 4}} = \dfrac{1}{{1296}}\]
3) \[{\left( {\dfrac{1}{{81}}} \right)^{\dfrac{3}{4}}} = \dfrac{1}{{27}}\]
4) \[{\left( {216} \right)^{\dfrac{1}{3}}} = 6\]
5) \[{\left( {13} \right)^{ - 1}} = \dfrac{1}{{13}}\]
Answer
465.3k+ views
Hint:
Here we will use the basic concept of conversion of the exponential to the logarithmic form. In order to change from exponential form to logarithmic form, we need to identify the base of the exponential equation and move the base to the other side of the equal sign. Then add the word log to the expression formed.
Complete step by step solution:
We know that the exponential form is \[{a^x} = b\] and logarithmic form is \[x = {\log _a}b\].
Now we will apply this to all the options.
1) Given exponential form is \[{3^4} = 81\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _3}81 = 4\].
2) Given exponential form is \[{6^{ - 4}} = \dfrac{1}{{1296}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _6}\left( {\dfrac{1}{{1296}}} \right) = - 4\].
3) Given exponential form is \[{\left( {\dfrac{1}{{81}}} \right)^{\dfrac{3}{4}}} = \dfrac{1}{{27}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{\dfrac{1}{{81}}}}\left( {\dfrac{1}{{27}}} \right) = \dfrac{3}{4}\].
4) Given exponential form is \[{\left( {216} \right)^{\dfrac{1}{3}}} = 6\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{216}}6 = \dfrac{1}{3}\].
5) Given exponential form is \[{\left( {13} \right)^{ - 1}} = \dfrac{1}{{13}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{13}}\left( {\dfrac{1}{{13}}} \right) = - 1\].
Note:
We should note that the value inside the log function should never be zero or negative; it should always be greater than zero. We need to remember that the value of the \[\log 10\] is equal to 1. The exponential function is a constant which is raised to some power. An exponential function is the inverse of the logarithmic function.
Some of the basic properties of logarithm is listed below:
\[\begin{array}{l}\log a + \log b = \log ab\\\log {a^b} = b\log a\\\log a - \log b = \log \dfrac{a}{b}\\{\log _a}b = \dfrac{{\log b}}{{\log a}}\end{array}\]
Here we will use the basic concept of conversion of the exponential to the logarithmic form. In order to change from exponential form to logarithmic form, we need to identify the base of the exponential equation and move the base to the other side of the equal sign. Then add the word log to the expression formed.
Complete step by step solution:
We know that the exponential form is \[{a^x} = b\] and logarithmic form is \[x = {\log _a}b\].
Now we will apply this to all the options.
1) Given exponential form is \[{3^4} = 81\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _3}81 = 4\].
2) Given exponential form is \[{6^{ - 4}} = \dfrac{1}{{1296}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _6}\left( {\dfrac{1}{{1296}}} \right) = - 4\].
3) Given exponential form is \[{\left( {\dfrac{1}{{81}}} \right)^{\dfrac{3}{4}}} = \dfrac{1}{{27}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{\dfrac{1}{{81}}}}\left( {\dfrac{1}{{27}}} \right) = \dfrac{3}{4}\].
4) Given exponential form is \[{\left( {216} \right)^{\dfrac{1}{3}}} = 6\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{216}}6 = \dfrac{1}{3}\].
5) Given exponential form is \[{\left( {13} \right)^{ - 1}} = \dfrac{1}{{13}}\]
Now by using the basic concept of the conversion of the exponential into logarithmic function, we get
Logarithmic form is \[{\log _{13}}\left( {\dfrac{1}{{13}}} \right) = - 1\].
Note:
We should note that the value inside the log function should never be zero or negative; it should always be greater than zero. We need to remember that the value of the \[\log 10\] is equal to 1. The exponential function is a constant which is raised to some power. An exponential function is the inverse of the logarithmic function.
Some of the basic properties of logarithm is listed below:
\[\begin{array}{l}\log a + \log b = \log ab\\\log {a^b} = b\log a\\\log a - \log b = \log \dfrac{a}{b}\\{\log _a}b = \dfrac{{\log b}}{{\log a}}\end{array}\]
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Truly whole mankind is one was declared by the Kannada class 10 social science CBSE

Explain the three major features of the shiwaliks class 10 social science CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

What is the corona radiata penetrating enzyme class 10 biology CBSE

What are the public facilities provided by the government? Also explain each facility

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
