How many changes can be rung with a peal of 5 bells.
Answer
Verified
476.4k+ views
Hint: Start from 1 bell and take the calculation up to 5 bells, first find the change of variation of 1 bell, find the change of variation of 2 bells, find the change of variation of 3 bells and so on, end this process when someone rang the bell 5 times in the same pattern.
Complete step by step answer:
We have given the $5$ bells about we have to find out the changes which can be rung.
When a bell rung only 1 time, then there will be only one change of variation, which can be written as,
$1! = 1$
When a bell rung only 2 times, then there will be only two changes of variation, which can be written as,
$
2! = 2 \times 1 \\
= 2 \\
$
When a bell rung only 3 times, then there will be only six changes of variation, which can be written as,
$
3! = 3 \times 2 \times 1 \\
= 6 \\
$
When a bell rung only 4 times, then there will be only twenty-four changes of variation, which can be written as,
$
4! = 4 \times 3 \times 2 \times 1 \\
= 24 \\
$
When a bell rung only 5 times, then there will be only 120 changes of variation, which can be written as,
$
5! = 5 \times 4 \times 3 \times 2 \times 1 \\
= 120 \\
$
$\therefore$ When a bell rang 5 times, 120 changes of variations were formed.
Note:
Use the concept of periodical repetition and the concept of factorial notation to simplify the calculations. Write the first and second numbers in factorial form instead of simple numbers, otherwise anyone may be confused if factorial notation is not there in the first and second numbers.
Complete step by step answer:
We have given the $5$ bells about we have to find out the changes which can be rung.
When a bell rung only 1 time, then there will be only one change of variation, which can be written as,
$1! = 1$
When a bell rung only 2 times, then there will be only two changes of variation, which can be written as,
$
2! = 2 \times 1 \\
= 2 \\
$
When a bell rung only 3 times, then there will be only six changes of variation, which can be written as,
$
3! = 3 \times 2 \times 1 \\
= 6 \\
$
When a bell rung only 4 times, then there will be only twenty-four changes of variation, which can be written as,
$
4! = 4 \times 3 \times 2 \times 1 \\
= 24 \\
$
When a bell rung only 5 times, then there will be only 120 changes of variation, which can be written as,
$
5! = 5 \times 4 \times 3 \times 2 \times 1 \\
= 120 \\
$
$\therefore$ When a bell rang 5 times, 120 changes of variations were formed.
Note:
Use the concept of periodical repetition and the concept of factorial notation to simplify the calculations. Write the first and second numbers in factorial form instead of simple numbers, otherwise anyone may be confused if factorial notation is not there in the first and second numbers.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success
Master Class 11 Computer Science: Engaging Questions & Answers for Success
Master Class 11 Maths: Engaging Questions & Answers for Success
Master Class 11 Social Science: Engaging Questions & Answers for Success
Master Class 11 Economics: Engaging Questions & Answers for Success
Master Class 11 Business Studies: Engaging Questions & Answers for Success
Trending doubts
10 examples of friction in our daily life
What problem did Carter face when he reached the mummy class 11 english CBSE
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
State and prove Bernoullis theorem class 11 physics CBSE
The sequence of spore production in Puccinia wheat class 11 biology CBSE