What is the colour of barium sulphate precipitate in the reaction of barium chloride and sodium sulphate?
Answer
Verified
392.7k+ views
Hint: Barium sulphate is an ionic compound consisting of barium and sulphate ions. Barium is an alkaline earth metal with a valency. Coloured salts are mainly formed by the transition metal ions that can show variable oxidation states and their electrons show d-d transition.
Complete answer:
The reaction between barium chloride and sodium sulphate is an example of a double displacement reaction where the anions and cations get interchanged giving rise to two new salts. The barium ion gets attracted to sulphate ions leaving behind chloride ions that form bonds with the free sodium ions. The reaction can be written as follows:
\[BaC{l_2}(aq) + N{a_2}S{O_4}(aq) \to BaS{O_4}(s) \downarrow + NaCl(aq)\]
The sodium chloride formed in the product is highly soluble and remains dissolved in the solution while the barium sulphate precipitates out as a white solid.
The precipitation observed in the case of barium sulphate is a consequence of its low solubility. Both the barium as well as sulphate ions are large in size and therefore less soluble in water.
The precipitate of barium sulphate is white in colour as the salt does not release any free electrons that undergo transitions in the visible energy range.
Note:
Solubility is determined by both lattice energy as well as hydration enthalpy. Smaller ions tend to have hydration enthalpy that excess lattice energy making the ionic solids more soluble. The presence of both the large sized ions in barium sulphate leads to a higher lattice energy than the hydration enthalpy making the salt less soluble and easy to precipitate.
Complete answer:
The reaction between barium chloride and sodium sulphate is an example of a double displacement reaction where the anions and cations get interchanged giving rise to two new salts. The barium ion gets attracted to sulphate ions leaving behind chloride ions that form bonds with the free sodium ions. The reaction can be written as follows:
\[BaC{l_2}(aq) + N{a_2}S{O_4}(aq) \to BaS{O_4}(s) \downarrow + NaCl(aq)\]
The sodium chloride formed in the product is highly soluble and remains dissolved in the solution while the barium sulphate precipitates out as a white solid.
The precipitation observed in the case of barium sulphate is a consequence of its low solubility. Both the barium as well as sulphate ions are large in size and therefore less soluble in water.
The precipitate of barium sulphate is white in colour as the salt does not release any free electrons that undergo transitions in the visible energy range.
Note:
Solubility is determined by both lattice energy as well as hydration enthalpy. Smaller ions tend to have hydration enthalpy that excess lattice energy making the ionic solids more soluble. The presence of both the large sized ions in barium sulphate leads to a higher lattice energy than the hydration enthalpy making the salt less soluble and easy to precipitate.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
State and prove Bernoullis theorem class 11 physics CBSE
What organs are located on the left side of your body class 11 biology CBSE