Answer
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Hint: y = 4x is a line passing through the origin. It's the slope is m. We found the slope of the point using the slope-intercept form of the line which is $y=mx+c$ . On comparing we obtain the slope. So we can find all the points which satisfy this line equation. Or if we know one coordinate of a point lying on this line, then we can obtain the other by this line equation.
Complete step-by-step solution:
According to the question, we have been given a point namely, (0,?).
Let us assume this ? to be a . So now the point is (0,a). And we are told that this point satisfies the line y = 4x.
We know that the line y = 4x passes through the X-axis as the abscissa is 0 in the line equation.
(0,a) satisfies y = 4x.
$\Rightarrow a=4\left( 0 \right)$
And on further simplifications, we get
$\Rightarrow a=0$
Therefore, the graph of y = 4x will look like the following:
And the ordered pair which satisfies the equation y = 4x is (0,0).
Note: Please be careful with the line equation or any other equation which is given to you. Remember all the general equations of the line so as to quickly solve the equation. Especially in this question, if we are able to remember that when the constant term is 0 then it passes through the origin then we can directly answer this question.
Complete step-by-step solution:
According to the question, we have been given a point namely, (0,?).
Let us assume this ? to be a . So now the point is (0,a). And we are told that this point satisfies the line y = 4x.
We know that the line y = 4x passes through the X-axis as the abscissa is 0 in the line equation.
(0,a) satisfies y = 4x.
$\Rightarrow a=4\left( 0 \right)$
And on further simplifications, we get
$\Rightarrow a=0$
Therefore, the graph of y = 4x will look like the following:
And the ordered pair which satisfies the equation y = 4x is (0,0).
Note: Please be careful with the line equation or any other equation which is given to you. Remember all the general equations of the line so as to quickly solve the equation. Especially in this question, if we are able to remember that when the constant term is 0 then it passes through the origin then we can directly answer this question.
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