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How will you convert benzene into m-nitro chlorobenzene?

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Hint: We know that m-nitro chlorobenzene is $1 - $chloro$ - 3 - $nitro benzene can be synthesised by the substitution reaction on a benzene ring. We can convert benzene in m-nitro chlorobenzene by nitration of benzene followed by chlorination of the compound formed by nitration.

Step-By-Step answer:
Nitration of benzene happens when one or more than one hydrogen atom from the benzene ring is replaced by a nitro group. To accomplish this reaction benzene is treated with concentrated nitric acid and concentrated sulphuric acid at a temperature not more than ${50^0}$ C. The nitration mechanism involves the formation of nitronium ions. An electrophilic substitution reaction occurs between benzene and nitric acid.
Chlorination of nitrobenzene is also an electrophilic substitution reaction where chloronium ion acts as an electrophile. Chloronium ion attacks on the nitrobenzene on the nitrobenzene ring. The attack is possible at three positions, ortho, meta and para position of nitrobenzene ring. But meta attack is more stable in comparison to ortho and para attack. Thus the chlorination gives meta nitrobenzene as a major product. Ferric chloride or aluminium chloride is used as a catalyst to give chloronium ion. The reaction of converting benzene to m-nitro chlorobenzene is given below;

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Note: This is a compound which is used in synthesis of various compounds. m-nitrochlorobenzene is an important intermediate of pharmaceuticals and dyes. It is used in the production of chloroaniline, azo dyes, pesticides, drugs, pigments etc. It is a precursor to other compounds due to the presence of the two relative sites on the molecules. Purification of m-nitro chlorobenzene is difficult since other isomers are formed during chlorination of nitrobenzene.