How can I convert L-xylose bond line view to Fischer projection?
Answer
Verified
417k+ views
Hint: We know that using wedge and dash notation, solid lines (sticks) represent chemical bonds in the plane of the surface. Black wedges represent chemical bonds coming toward you, while dashed lines are for bonds that extend back behind the surface.
Complete step by step solution:
A Fischer projection represents every chiral center as a cross. The horizontal line represents bonds extending out of the plane of the paper. The vertical line represents bonds extending behind the plane of the paper. The Fischer projection of L-xylose is
Here's how to convert the wedge-dash structure of L-xylose to its Fischer projection.
Arrange the molecule so that the chiral carbons and the longest continuous chain are in a vertical line. $ C-1 $ (the aldehyde group) goes at the top.
Draw horizontal lines to make crosses at $ C-2,\text{ }C-3, $ and $ C-4. $
Put the $ C-4\text{ }OH $ group on the correct side of the cross. We must view the molecule from the correct angle. This is an L-sugar, so the $ OH $ must be on the left, and $ C-4 $ must be closest to our eye. We must view the molecule from the lower left. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right.
Put the $ C-3\text{ }OH $ group on the correct side of the cross. The $ OH $ is on the left, but $ C-3 $ is furthest from our eye. We must rotate $ C-3 $ to bring it near our eye. The $ OH $ then rotates to the right. We put the $ OH $ on the right arm of the cross. The $ H $ atom goes on the left.
Put the $ C-2\text{ }OH $ group on the correct side of the cross. The $ OH $ group is on the left, and $ C-2 $ is closest to our eye. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right. We now have the Fischer projection of L-xylose.
Note:
Remember that the wedges are now on the right, and the dashes are on the left. It is as if we had wrapped the chain around a cylindrical tube. When you flatten the structure onto the surface of the cylinder, you get the Fischer projection of D-glucose. Understanding the concept of wedge and dash helps to understand stereochemistry and spectroscopy which is an important aspect in research.
Complete step by step solution:
A Fischer projection represents every chiral center as a cross. The horizontal line represents bonds extending out of the plane of the paper. The vertical line represents bonds extending behind the plane of the paper. The Fischer projection of L-xylose is
Here's how to convert the wedge-dash structure of L-xylose to its Fischer projection.
Arrange the molecule so that the chiral carbons and the longest continuous chain are in a vertical line. $ C-1 $ (the aldehyde group) goes at the top.
Draw horizontal lines to make crosses at $ C-2,\text{ }C-3, $ and $ C-4. $
Put the $ C-4\text{ }OH $ group on the correct side of the cross. We must view the molecule from the correct angle. This is an L-sugar, so the $ OH $ must be on the left, and $ C-4 $ must be closest to our eye. We must view the molecule from the lower left. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right.
Put the $ C-3\text{ }OH $ group on the correct side of the cross. The $ OH $ is on the left, but $ C-3 $ is furthest from our eye. We must rotate $ C-3 $ to bring it near our eye. The $ OH $ then rotates to the right. We put the $ OH $ on the right arm of the cross. The $ H $ atom goes on the left.
Put the $ C-2\text{ }OH $ group on the correct side of the cross. The $ OH $ group is on the left, and $ C-2 $ is closest to our eye. We put the $ OH $ on the left arm of the cross. The $ H $ atom goes on the right. We now have the Fischer projection of L-xylose.
Note:
Remember that the wedges are now on the right, and the dashes are on the left. It is as if we had wrapped the chain around a cylindrical tube. When you flatten the structure onto the surface of the cylinder, you get the Fischer projection of D-glucose. Understanding the concept of wedge and dash helps to understand stereochemistry and spectroscopy which is an important aspect in research.
Recently Updated Pages
Can anyone list 10 advantages and disadvantages of friction
What are the Components of Financial System?
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Which is not a source of freshwater 1 Glaciers and class 11 chemistry CBSE
10 examples of friction in our daily life
The correct order of melting point of 14th group elements class 11 chemistry CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
What is the specific heat capacity of ice water and class 11 physics CBSE