Answer
397.5k+ views
Hint: We are given with the dimensions of a cuboidal room. In order to paint the walls and ceiling of the room only the base of the room is to be left. So we will paint 4 walls and the ceiling. Now we will find the areas of the walls and ceiling. Then on adding them we will get the total area that is to be painted. And after finding the area we will divide the area by the area that is getting painted in one can in order to find the number of cans required to paint the room.
Complete Step by Step Solution:
Given is a cuboid room that Daniel is painting. So in order to paint we should have the idea of what area of room we have to paint. So there are 4 walls and 1 ceiling. We have drawn the diagram of this room.
Now
\[are{a_{front{\text{ }}wall{\text{ }} + back{\text{ }}wall}} = 2\left( {l \times h} \right) = 2\left( {15 \times 7} \right) = 210{m^2}\]
\[are{a_{Two{\text{ }}side{\text{ }}walls}} = 2\left( {h \times b} \right) = 2\left( {7 \times 10} \right) = 140{m^2}\]
\[are{a_{ceiling}} = l \times b = 15 \times 10 = 150{m^2}\]
Total area to be painted is given by,
\[{\text{Total area to be painted = }}are{a_{front{\text{ }}wall{\text{ }} + back{\text{ }}wall}} + are{a_{Two{\text{ }}side{\text{ }}walls}} + are{a_{ceiling}}\]
Putting the areas we get,
\[{\text{Total area to be painted = 210 + 140 + 150 = 500}}{{\text{m}}^2}\]
Now number of cans required to paint the room = \[\dfrac{{Total{\text{ }}area{\text{ }}to{\text{ }}be{\text{ }}pa\operatorname{int} ed}}{{Area{\text{ }}painted{\text{ }}in{\text{ }}one{\text{ }}can}}\]
\[ \Rightarrow \dfrac{{500}}{{100}} = 5\]
So, Daniel will require 5 cans to paint her room.
Note:
Note that we are finding the number of cans required so don’t multiply the area with the area painted in one can. That is not the way to solve the question. Also we have considered the ceiling but don’t consider the base of the room. Also if in problem any window or door is given we will remove the area of that part also.
Complete Step by Step Solution:
Given is a cuboid room that Daniel is painting. So in order to paint we should have the idea of what area of room we have to paint. So there are 4 walls and 1 ceiling. We have drawn the diagram of this room.
![seo images](https://www.vedantu.com/question-sets/463d9422-1181-46f8-961d-6ec5606246214354199687677386900.png)
Now
\[are{a_{front{\text{ }}wall{\text{ }} + back{\text{ }}wall}} = 2\left( {l \times h} \right) = 2\left( {15 \times 7} \right) = 210{m^2}\]
\[are{a_{Two{\text{ }}side{\text{ }}walls}} = 2\left( {h \times b} \right) = 2\left( {7 \times 10} \right) = 140{m^2}\]
\[are{a_{ceiling}} = l \times b = 15 \times 10 = 150{m^2}\]
Total area to be painted is given by,
\[{\text{Total area to be painted = }}are{a_{front{\text{ }}wall{\text{ }} + back{\text{ }}wall}} + are{a_{Two{\text{ }}side{\text{ }}walls}} + are{a_{ceiling}}\]
Putting the areas we get,
\[{\text{Total area to be painted = 210 + 140 + 150 = 500}}{{\text{m}}^2}\]
Now number of cans required to paint the room = \[\dfrac{{Total{\text{ }}area{\text{ }}to{\text{ }}be{\text{ }}pa\operatorname{int} ed}}{{Area{\text{ }}painted{\text{ }}in{\text{ }}one{\text{ }}can}}\]
\[ \Rightarrow \dfrac{{500}}{{100}} = 5\]
So, Daniel will require 5 cans to paint her room.
Note:
Note that we are finding the number of cans required so don’t multiply the area with the area painted in one can. That is not the way to solve the question. Also we have considered the ceiling but don’t consider the base of the room. Also if in problem any window or door is given we will remove the area of that part also.
Recently Updated Pages
Mark and label the given geoinformation on the outline class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
When people say No pun intended what does that mea class 8 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Name the states which share their boundary with Indias class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give an account of the Northern Plains of India class 9 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Advantages and disadvantages of science
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Bimbisara was the founder of dynasty A Nanda B Haryanka class 6 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
10 examples of evaporation in daily life with explanations
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How do you graph the function fx 4x class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)