Answer
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Hint: To know the definition of magnetic declination, we need to know about the magnetic Meridian and the geometrical Meridian. Then we will know about the dip angle and we will try to know about the horizontal component of Earth’s magnetic field. Then we can solve this problem easily.
Formula used:
$H=I.\cos\theta$
Complete step-by-step solution:
If a magnetic bar is tied with a thread exactly at its center of gravity, and then hanged, then it does not exactly point towards North and the South, but it is a little inclined. Now, the vertical plane through which the axis of this magnet passes is called the magnetic Meridian. And the vertical plane that passes through the geometrical North and South Pole is called the geometrical Meridian. So, the geometrical and magnetic Meridian are not the same, but they make an angle to each other.
The angle between the geometrical Meridian and the magnetic Meridian at a certain place is defined as the magnetic declination of that place.
Now, dip angle is the angle that the magnetic bar makes with the horizontal plane. Let this dip angle be $\theta$ . If I be the magnetic field of at a certain place, the horizontal component of Earth’s magnetic field is given by,
$H=I.\cos\theta$
In this place we have, $\theta=60^\circ$. And I=0.25 gauss.
Putting these values in the above question, we easily obtain that I= 0.50 gauss.
So, the required answer of the given question is that, at the given place the value of Earth’s magnetic field is 0.50 gauss.
Additional information: The value of the vertical component of earth’s magnetic field is given by, $V=I.\sin\theta$. If one knows the vertical and horizontal component of earth’s magnetic field at a certain place, then,
$I=\sqrt{V^2+H^2}$
Note: Never confuse between magnetic declination and the dip angle of Earth. Remember that geometrical meridian and magnetic Meridian is not the same. Also, Earth’s magnetic field, (I) will be in the same unit as the horizontal field, H.
Formula used:
$H=I.\cos\theta$
Complete step-by-step solution:
If a magnetic bar is tied with a thread exactly at its center of gravity, and then hanged, then it does not exactly point towards North and the South, but it is a little inclined. Now, the vertical plane through which the axis of this magnet passes is called the magnetic Meridian. And the vertical plane that passes through the geometrical North and South Pole is called the geometrical Meridian. So, the geometrical and magnetic Meridian are not the same, but they make an angle to each other.
The angle between the geometrical Meridian and the magnetic Meridian at a certain place is defined as the magnetic declination of that place.
Now, dip angle is the angle that the magnetic bar makes with the horizontal plane. Let this dip angle be $\theta$ . If I be the magnetic field of at a certain place, the horizontal component of Earth’s magnetic field is given by,
$H=I.\cos\theta$
In this place we have, $\theta=60^\circ$. And I=0.25 gauss.
Putting these values in the above question, we easily obtain that I= 0.50 gauss.
So, the required answer of the given question is that, at the given place the value of Earth’s magnetic field is 0.50 gauss.
Additional information: The value of the vertical component of earth’s magnetic field is given by, $V=I.\sin\theta$. If one knows the vertical and horizontal component of earth’s magnetic field at a certain place, then,
$I=\sqrt{V^2+H^2}$
Note: Never confuse between magnetic declination and the dip angle of Earth. Remember that geometrical meridian and magnetic Meridian is not the same. Also, Earth’s magnetic field, (I) will be in the same unit as the horizontal field, H.
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