How many double bond equivalents (degrees of unsaturation) are in 2,2,3,3-tetramethyl-4-octyne?
Answer
Verified
374.4k+ views
Hint: The degree of unsaturation is a computation that calculates the total number of rings and $\pi $ bonds in an organic molecule's chemical formula. In organic chemistry, a formula is used to aid in the drawing of chemical structures. It provides no information about the individual components, such as the number of rings, double bonds (one $\pi $ bond each), or triple bonds (two $\pi $ bonds each).
Complete answer:
An alkyne is an unsaturated hydrocarbon with at least one carbon—carbon triple bond in organic chemistry. With only one triple bond and no additional functional groups, the simplest acyclic alkynes form a homologous series with the generic chemical formula ${C_n}{H_{2n - 2}}$.
The standard formula for computing the double bond equivalent (DBE) is:
\[{\text{DBE = C - }}\dfrac{{\text{H}}}{{\text{2}}}{\text{ + }}\dfrac{{\text{N}}}{{\text{2}}}{\text{ + 1}}\]
where C denotes the number of carbon atoms, H denotes the amount of hydrogen and halogen atoms, and N denotes the number of nitrogen atoms in the molecule if any exist.
The molecular formula of 2,2,3,3-tetramethyl-4-octyne can be given as \[{C_{12}}{H_{22}}\]
There dbe equals
\[{\text{DBE = 12 - }}\dfrac{{22}}{{\text{2}}}{\text{ + }}\dfrac{0}{{\text{2}}}{\text{ + 1 = 12 - 11 + 1 = 13 - 11 = 2 }}\]
NMR, mass spectrometry, and IR spectroscopy, as well as qualitative examination, are used to verify the final structure. It works by comparing the current molecular formula to what may be a potential formula if the structure was saturated (no rings and just bonds) and all atoms had their normal valence.
Note:
Because joining two elements to form a ring or adding one extra bond in a structure reduces the need for two H's, the DBE (or IHD) for hydrocarbons tells us the number of rings and/or extra bonds in a non-saturated structure, which equals the number of hydrogen pairs required to make the structure saturated. For non-hydrocarbons, the elements in a pair can be any elements from the periodic table's lithium and fluorine families, although not necessarily all H's.
Complete answer:
An alkyne is an unsaturated hydrocarbon with at least one carbon—carbon triple bond in organic chemistry. With only one triple bond and no additional functional groups, the simplest acyclic alkynes form a homologous series with the generic chemical formula ${C_n}{H_{2n - 2}}$.
The standard formula for computing the double bond equivalent (DBE) is:
\[{\text{DBE = C - }}\dfrac{{\text{H}}}{{\text{2}}}{\text{ + }}\dfrac{{\text{N}}}{{\text{2}}}{\text{ + 1}}\]
where C denotes the number of carbon atoms, H denotes the amount of hydrogen and halogen atoms, and N denotes the number of nitrogen atoms in the molecule if any exist.
The molecular formula of 2,2,3,3-tetramethyl-4-octyne can be given as \[{C_{12}}{H_{22}}\]
There dbe equals
\[{\text{DBE = 12 - }}\dfrac{{22}}{{\text{2}}}{\text{ + }}\dfrac{0}{{\text{2}}}{\text{ + 1 = 12 - 11 + 1 = 13 - 11 = 2 }}\]
NMR, mass spectrometry, and IR spectroscopy, as well as qualitative examination, are used to verify the final structure. It works by comparing the current molecular formula to what may be a potential formula if the structure was saturated (no rings and just bonds) and all atoms had their normal valence.
Note:
Because joining two elements to form a ring or adding one extra bond in a structure reduces the need for two H's, the DBE (or IHD) for hydrocarbons tells us the number of rings and/or extra bonds in a non-saturated structure, which equals the number of hydrogen pairs required to make the structure saturated. For non-hydrocarbons, the elements in a pair can be any elements from the periodic table's lithium and fluorine families, although not necessarily all H's.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success
Master Class 11 Computer Science: Engaging Questions & Answers for Success
Master Class 11 Maths: Engaging Questions & Answers for Success
Master Class 11 Social Science: Engaging Questions & Answers for Success
Master Class 11 Economics: Engaging Questions & Answers for Success
Master Class 11 Business Studies: Engaging Questions & Answers for Success
Trending doubts
10 examples of friction in our daily life
What problem did Carter face when he reached the mummy class 11 english CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
State and prove Bernoullis theorem class 11 physics CBSE
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
Petromyzon belongs to class A Osteichthyes B Chondrichthyes class 11 biology CBSE