
Draw a line segment AB of length 8cm. Taking A as centre, draw a circle of radius 4cm and taking B as centre, draw another circle of radius 3cm. Construct tangents to each circle from the centre of the other circle.
Answer
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Hint: Here we will proceed by constructing a line segment of given measurement. Also with both the radius given we will draw two circles such that they intersected by a new circle formed. Further we will join the intersected points which will form the required tangents.
Complete step-by-step answer:
Steps of construction-
(1) A line segment AB of 8cm is drawn.
(2) With A as centre and radius equal to 4cm, a circle is drawn.
(3) With B as centre and radius equal to 3cm, a circle is drawn.
Now we need to draw tangent from point A to the right circle, and from point B to the left circle. To draw tangents to the right circle, we need to draw a perpendicular bisector of line AB.
(4) Make a perpendicular bisector of AB. Let M be the mid-point of AB.
(5) Taking M as centre and MA as radius, draw a circle.
(6) Let the middle circle intersect the left circle at P, Q and right circle at R, S.
(7) Join BP, BQ, AR and AS.
(8) Thus BP, BQ, AR and AS are the required tangents.
Note: In order to solve this question, one can get confused while constructing circles with different radius such that a new circle formed should be intersected by the previous circles. Also we must concentrate that the required tangents will be formed from the intersection points of the new circle formed.
Complete step-by-step answer:
Steps of construction-
(1) A line segment AB of 8cm is drawn.

(2) With A as centre and radius equal to 4cm, a circle is drawn.
(3) With B as centre and radius equal to 3cm, a circle is drawn.

Now we need to draw tangent from point A to the right circle, and from point B to the left circle. To draw tangents to the right circle, we need to draw a perpendicular bisector of line AB.
(4) Make a perpendicular bisector of AB. Let M be the mid-point of AB.

(5) Taking M as centre and MA as radius, draw a circle.

(6) Let the middle circle intersect the left circle at P, Q and right circle at R, S.
(7) Join BP, BQ, AR and AS.

(8) Thus BP, BQ, AR and AS are the required tangents.
Note: In order to solve this question, one can get confused while constructing circles with different radius such that a new circle formed should be intersected by the previous circles. Also we must concentrate that the required tangents will be formed from the intersection points of the new circle formed.
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