
Draw an equilateral triangle whose sides are 5.2 centimeter each.
Answer
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Hint: An equilateral triangle having a size of 5.2 centimeters. so we draw each side of length 5.2 centimeter. We should use a ruler for accuracy.
Complete step by step solution:
(i)First we will draw a line segment AB of length 5.2 centimeter using a ruler.
(ii)Then we will take a compass opening 5.2 centimeter and marking the length on the compass.
(iii)Putting the end of the compass on point A and drawing in an arc with a radius 5.2 centimeter. Now we will put the same compass with the same length on point B and draw an Arc again. This arc will further intersect with the previous arc made from point A. The point at which these two arcs meet will be point C. Join the line A to C and B To C forming a line segment AB and BC which are the sides of an equilateral triangle of length 5.2 centimeter each.
Additional information: In general, the height of an equilateral triangle is equal to \[\dfrac{\sqrt{3}}{2}\] times a side of the equilateral triangle. The area of an equilateral triangle is equal to
\[\dfrac{1}{2}\times \dfrac{\sqrt{3}a}{2}\times a=\dfrac{\sqrt{3}}{4}{{a}^{2\text{ }}}\ \text{ }\!\![\!\!\text{ }a\text{ is the side of the triangle }\!\!]\!\!\text{ }\]
Note: Thus to check if the triangle is an equilateral triangle we can draw \[{{60}^{\circ }}\]arc at the three points of the triangle and check if all three of them are \[{{60}^{\circ }}\] or not. If all three have \[{{60}^{\circ }}\] internal angle then it is an equilateral triangle.
Complete step by step solution:
(i)First we will draw a line segment AB of length 5.2 centimeter using a ruler.
(ii)Then we will take a compass opening 5.2 centimeter and marking the length on the compass.
(iii)Putting the end of the compass on point A and drawing in an arc with a radius 5.2 centimeter. Now we will put the same compass with the same length on point B and draw an Arc again. This arc will further intersect with the previous arc made from point A. The point at which these two arcs meet will be point C. Join the line A to C and B To C forming a line segment AB and BC which are the sides of an equilateral triangle of length 5.2 centimeter each.

Additional information: In general, the height of an equilateral triangle is equal to \[\dfrac{\sqrt{3}}{2}\] times a side of the equilateral triangle. The area of an equilateral triangle is equal to
\[\dfrac{1}{2}\times \dfrac{\sqrt{3}a}{2}\times a=\dfrac{\sqrt{3}}{4}{{a}^{2\text{ }}}\ \text{ }\!\![\!\!\text{ }a\text{ is the side of the triangle }\!\!]\!\!\text{ }\]
Note: Thus to check if the triangle is an equilateral triangle we can draw \[{{60}^{\circ }}\]arc at the three points of the triangle and check if all three of them are \[{{60}^{\circ }}\] or not. If all three have \[{{60}^{\circ }}\] internal angle then it is an equilateral triangle.
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