Question

How many electrons are transferred during the following change?
\[2{{I}^{-}}_{(aq)}\to {{I}_{2}}_{(s)}\]

Answer 1

Hint: During the process of oxidation and reduction the transfer of electrons is going to take place between different chemicals. The process of losing the electrons is called oxidation and the process of gaining of electrons is called reduction.

Complete answer:
- In the question it is given to find the number of electrons transferred during the given chemical reaction.
- The given chemical reaction is as follows.
\[2{{I}^{-}}_{(aq)}\to {{I}_{2}}_{(s)}\]
- In the above chemical reaction two moles of iodide anion is going to convert into one mole of iodine.
- Now we have to find the number of electrons released from the iodide anion while it is going to convert into iodine.
- The oxidation number of the iodide anion is ‘-1’’, and the oxidation number of the iodine is zero.
- Therefore, in the chemical reaction two iodide anions are going to convert into one mole of iodine.
- Means two electrons are going to be released by the two iodide anions and converting into one mole of iodine.
- Therefore, the complete chemical reaction can be written as follows.
\[2{{I}^{-}}_{(aq)}\to {{I}_{2}}_{(s)}+2{{e}^{-}}\]
- In the above reaction we can say that two electrons are going to be transferred during the given chemical reaction.

Note:
During oxidation chemical reaction electrons are going to be released and during reduction chemical reaction the electrons are going to be accepted by the reactants in the chemical reaction. In redox chemical reactions both oxidation and reduction reactions are going to take place together.