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What is the equation for: Gaseous ammonia reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water?
Answer
419.1k+ views
Hint: A chemical equation consists of the substances that react called as reactants and the new substances that are formed by the reaction called as products. A balanced chemical equation can tell the quantities of all the reactants involved and the products formed. Gaseous water is the gas phase of water generally water vapors.
Complete answer:
A chemical equation is the representation of the reaction that takes place when two or more substances react together to form various new products. The chemical equations require balancing, which is a method to represent the exact number of moles involved and formed after the reaction.
We have been given, gaseous ammonia $N{{H}_{3}}$ that reacts with gaseous oxygen ${{O}_{2}}$ to produce nitrogen monoxide $NO$ and water ${{H}_{2}}O$ both in gaseous state. The equation will be,
$N{{H}_{3}}(g)+{{O}_{2}}(g)\to NO(g)+{{H}_{2}}O(g)$ , to balance it we will look at the quantities of each atoms in the reactants and the products. For this we will write 4 in front of ammonia and nitrogen monoxide, and 5 for oxygen gas, and 6 for water. Then the equation will become,
$4N{{H}_{3}}(g)+5{{O}_{2}}(g)\to 4NO(g)+6{{H}_{2}}O(g)$, which is a balanced equation.
Hence, the equation for gaseous ammonia reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water is $4N{{H}_{3}}(g)+5{{O}_{2}}(g)\to 4NO(g)+6{{H}_{2}}O(g)$.
Note:
The equation is a type of redox reaction as the charge of nitrogen in ammonia increases from -3 to +2 and that of oxygen decreases from 0 to -2. The oxidation state of any compound or atom in its elementary form is 0. Redox reactions are the reactions in which reduction and oxidation happens simultaneously. Here ammonia is going through oxidation and oxygen is going through reduction.
Complete answer:
A chemical equation is the representation of the reaction that takes place when two or more substances react together to form various new products. The chemical equations require balancing, which is a method to represent the exact number of moles involved and formed after the reaction.
We have been given, gaseous ammonia $N{{H}_{3}}$ that reacts with gaseous oxygen ${{O}_{2}}$ to produce nitrogen monoxide $NO$ and water ${{H}_{2}}O$ both in gaseous state. The equation will be,
$N{{H}_{3}}(g)+{{O}_{2}}(g)\to NO(g)+{{H}_{2}}O(g)$ , to balance it we will look at the quantities of each atoms in the reactants and the products. For this we will write 4 in front of ammonia and nitrogen monoxide, and 5 for oxygen gas, and 6 for water. Then the equation will become,
$4N{{H}_{3}}(g)+5{{O}_{2}}(g)\to 4NO(g)+6{{H}_{2}}O(g)$, which is a balanced equation.
Hence, the equation for gaseous ammonia reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water is $4N{{H}_{3}}(g)+5{{O}_{2}}(g)\to 4NO(g)+6{{H}_{2}}O(g)$.
Note:
The equation is a type of redox reaction as the charge of nitrogen in ammonia increases from -3 to +2 and that of oxygen decreases from 0 to -2. The oxidation state of any compound or atom in its elementary form is 0. Redox reactions are the reactions in which reduction and oxidation happens simultaneously. Here ammonia is going through oxidation and oxygen is going through reduction.
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